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What rate of interest compounded annually is required to double an investment in 24 years?
If you start with an investment of I and the interest rate is r% per annum (compounded), then you want a solution to2I = I(1 + r/100)24or I = (1 + r/100)24That is ln(2) = 24*ln(1 + r/100)so that ln(1 + r/100) = ln(2)/24 = 0.02888or (1 + r/100) = exp(0.02888) = 1.0293and so r/100 = 0.0293 so that r = 2.93%If you start with an investment of I and the interest rate is r% per annum (compounded), then you want a solution to2I = I(1 + r/100)24or I = (1 + r/100)24That is ln(2) = 24*ln(1 + r/100)so that ln(1 + r/100) = ln(2)/24 = 0.02888or (1 + r/100) = exp(0.02888) = 1.0293and so r/100 = 0.0293 so that r = 2.93%If you start with an investment of I and the interest rate is r% per annum (compounded), then you want a solution to2I = I(1 + r/100)24or I = (1 + r/100)24That is ln(2) = 24*ln(1 + r/100)so that ln(1 + r/100) = ln(2)/24 = 0.02888or (1 + r/100) = exp(0.02888) = 1.0293and so r/100 = 0.0293 so that r = 2.93%If you start with an investment of I and the interest rate is r% per annum (compounded), then you want a solution to2I = I(1 + r/100)24or I = (1 + r/100)24That is ln(2) = 24*ln(1 + r/100)so that ln(1 + r/100) = ln(2)/24 = 0.02888or (1 + r/100) = exp(0.02888) = 1.0293and so r/100 = 0.0293 so that r = 2.93%
What is the interest rate needed for an investment of 7000 to grow to an amount of 9500 in 3 years if interest is compound monthly?
The formula to calculate the present amount including compound interest is, A = P(1 + r/n)nt , where P is the principal amount, r is the annual rate expressed as a decimal , t is the number of years, and n is number of times per year that interest is compounded. 9500 = 7000(1 + r/12)^(12 x 3) = 7000(1 + r/12)^36 Then, (1 + r/12)^36 = 9500 / 7000 = 1.3571429 approx (1 + r/12) = 36√1.3571429 ≅ 1.0085189 r/12 = 0.0085189 r = 12 x 0.0085189 ≅ 0.1022268 Then the required interest rate is 10.223% (3dp)
When all required information is available to solve a problem it can be said that it is an?
A well-structured problem has all the required information to solve it.
When all required information is available to solve a problem it can be said it is a?
A well-structured problem has all the required information to solve it.
Equalizing connections are required when paralleling two?
Equalizing connections are required when parallelingtwo compound generators and paralleling two Series generator .
