A rational function is undefined - you might say that it "has a hole" - at any point where the denominator is zero. Assuming you mean "... hole at x = 2", any rational function which has the factor (x-2) in its denominator will have a hole at x = 2.
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Any function, which in its simplified form, has a factor of (x - 2) in the denominator is undefined for x = 2. I am not sure if this constitutes a "hole".
Nope not all the rational functions have a horizontal asymptote
(x - u)*(x - u)*(x + 2i)*(x - 2i) = (x2 - 2xu + u2)*(x2 + 4) = x4 - 2x3u + x2(u2 + 4) - 8xu + 4u2
That's the definition of a "rational function". You simply divide a polynomial by another polynomial. The result is called a "rational function".
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