A rational function is undefined - you might say that it "has a hole" - at any point where the denominator is zero. Assuming you mean "... hole at x = 2", any rational function which has the factor (x-2) in its denominator will have a hole at x = 2.
(x - u)*(x - u)*(x + 2i)*(x - 2i) = (x2 - 2xu + u2)*(x2 + 4) = x4 - 2x3u + x2(u2 + 4) - 8xu + 4u2
Nope not all the rational functions have a horizontal asymptote
That's the definition of a "rational function". You simply divide a polynomial by another polynomial. The result is called a "rational function".
yes
false
Because they are represented as fractions.
x2 + 18x - 50 does not have rational factors.
Yes.
x3 - x2 + x - 2 has no rational factors.
I do not believe that there are any rational roots.
x^2 + 11x + 6 has no rational zeros.
Yes. Rational functions must contain rational expressions in order to be rational.
Yes. Rational functions must contain rational expressions in order to be rational.
Yes. Rational functions must contain rational expressions in order to be rational.
Yes. Rational functions must contain rational expressions in order to be rational.
Rational values- those are necessary to the functions and fulfillment of intellect and will.
When x = -3