x^2 + 11x + 6 has no rational zeros.
x3 + x2 - 17x + 15 = (x - 1)(x - 3)(x + 5). Thus, the zeros are 1, 3, and -5. All three zeros are rational.
X2 -11x +10=(x - 1 )(x - 10)
x^3 - 121x
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
It is: x^2 +11x +24 = (x+8)(x+3) when factored
X2+11x+11 = 7x+9 X2+11x-7x+11-9 = 0 x2+4x+2 = 0 Solve as a quadratic equation by using the quadratic equation formula or by completing the square: x = -2 + or - the square root of 2
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
-x2 - 11x + 26 = -(x2 + 11x - 26) = -(x2 - 2x + 13x - 26) = -[ x(x - 2) + 13(x - 2) ] = -(x + 13)(x - 2) = (x + 13)(2 - x)
It cannot be factored because the discriminant is less than zero. Do you mean x2+11x-60 then if so it is (x-4)(x+15)
x2 + 11x + 18 (x + 9)(x + 2) CHECK: x2 + 9x + 2x + 18 x2 + 11x + 18 SET EACH EQUAL TO ZERO: x + 9 = 0 x = -9 x + 2 = 0 x = -2 NOW YOU ARE DONE: Solution set: {-9, -2}
(x + 15)(x - 4)