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Q: How do you graph x y2?
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Related questions

Can a graph be symmetrical about the x axis?

X = y2 =====


How can you calculate a slope of graph?

Points: (x, y) and (x, y) Slope: y1-y2/x1-x2


How do you graph y2x?

y2x is an expression, which cannot be graphed because we don't know what it equals. y = 2x, y2 = x, and 2y (or y2) = x are all things that could actually be graphed.


How can you graph x2 - y2 equals 9?

Therefore x2=9+y2. And x is the square-root of that (with two values plus and minus). Choose a value of y, and work out x2 and therefore the values of x. Plot the two (+ and -) on a graph and continue for more values of y.


What is y to the 8th power as an product in four different was with only positive exponents?

y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2


What does the graph for X equals y2 plus 1 look like?

im not sure sure but i think it is squares on paper and a graph then put the information on to it durr.... ;]


How do you solve (x y2)(x-y2)?

0


How do you find the gradient of velocity time graph?

to calculate the area of any straight line graph or part of a graph, you need to select two points. for example (x1,y1) and (x2,y2). once you have selected the points you put then into the equation m=delta y/delta x (change in y divided by the change in x) which is easier as m=(y2-y1)/(x2-x1) and m = the gradient


How do you determine the slope of a line on an graph?

Rise divided by run. (Y2 - Y1) / (X2 - X1) - with (X1, Y1) and (X2, Y2) being two points on the graph.


A slope in a basic straight line graph?

Slope of a straight line on a Cartesian coordinated graph is 'rise over run' = y2-y1/x2-x1 = change in 'y'/change in 'x'


What is the slope of a line on a distance graph?

The slope is defined as rise/run or y/x. To solve it, you use 2 coordinates from that graph and use the formula m=X1/X2 - Y1/Y2.


How do you determine the slope of a straight line on a graph?

Slope of a straight line on a Cartesian coordinated graph is 'rise over run' = y2-y1/x2-x1 = change in 'y'/change in 'x'