Q: What two consecutive numbers make a product of 182?

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There are two consecutive even integers: 90 and 92.

Let the first number be x and the second number is 27 − x. [As the sum of both the numbers is 27] Therefore, their product = x (27 − x) It is given that the product of these numbers is 182. x (27 – x) = 182 x2 + 27x - 182 = 0 Changing the signs on both sides we get,x2 - 27x + 182 = 0 Factorizing we get , 13 and 14 are the numbers whose sum is 27 and product is 182 x2 – 13x – 14x + 182 = 0 = x(x – 13) – 14 (x – 13)= 0 = (x – 13) (x – 14) = 0 Either x – 13 = 0 or x − 14 = 0 i.e., x = 13 or x = 14 If first number = 13, then Other number = 27 − 13 = 14 If first number = 14, then Other number = 27 − 14 = 13 Therefore, the numbers are 13 and 14.

The integers are 180, 182 and 184.

2*91 13*14 7*26 1*182

Let a : b = 5 : 8If the unit part is x, then a = 5x and b = 8x. So we have:5x + 8x = 18213x = 182 divide both sides by 13x = 14Then,a = 5xa = 5 x 14a = 70b = 8xb = 8 x 14b = 112

Related questions

There is no set of four consecutive numbers with a product of 182. There is a set of four consecutive numbers with a sumof 182: 9, 20, 21 and 22.

13 x14 = 182

13 and 14

The numbers are 13 and 14.

182 = 2 x 7 x 13 so solution is 13 & 14

13 x 14 = 182

The two consecutive even numbers are 180 and 182.

13 x 14

13 and 14

There are two consecutive even integers: 90 and 92.

-13*-14 = 182

184