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Let the number be n & n+1 ; consecutive

Their product (multiplication) is

n(n+1) = 182

n^(2) + n = 182

n^(2) + n - 182 = 0

Factor

( n +14)(n - 13) = 0

Hence the numbers are 13, & 14.

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lenpollock

Lvl 16
8h ago

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