Let the first number be x and the second number is 27 − x.
[As the sum of both the numbers is 27]
Therefore, their product = x (27 − x)
It is given that the product of these numbers is 182.
x (27 – x) = 182
Changing the signs on both sides we get,x2 - 27x + 182 = 0
Factorizing we get , 13 and 14 are the numbers whose sum is 27 and product is 182
x2 – 13x – 14x + 182 = 0
= x(x – 13) – 14 (x – 13)= 0
= (x – 13) (x – 14) = 0
Either x – 13 = 0 or x − 14 = 0
i.e., x = 13 or x = 14
If first number = 13, then
Other number = 27 − 13 = 14
If first number = 14, then
Other number = 27 − 14 = 13
Therefore, the numbers are 13 and 14.
The numbers are 13 and 14.
182/100 = 91/50 or 1 and 41/50
2*91 13*14 7*26 1*182
13.490737563232
x^2 + (x+1 )^2 =365 x^2 +x^2 + 2x +1 =365 2x^2 + 2x = 364 x^2 + x = 182 = (x- 13)(x + 14) x =13, so integers are 13 and 14, squares 169 and 196, which total 365.
-13*-14 = 182
182 = 2 x 7 x 13 so solution is 13 & 14
13 x14 = 182
13 x 14 = 182
182.
There is no set of four consecutive numbers with a product of 182. There is a set of four consecutive numbers with a sumof 182: 9, 20, 21 and 22.
13 and 14. Also negative 13 and negative 14.
222
182.
The number 182 is "one hundred eighty-two."
130.The answer is given by 182/1.4
2 and 91