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What are Two integers whose product is 18 and whose sum is 11?
2 and 9 2*9 = 18 2+9 = 11
What two negative consecutive integers have a sum of -21?
-11 and -10
What is the the two consecutive negative integers whose product is 110?
-10 -11
What is the product of two consecutive integers that equals 132?
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
Find the three consecutive odd integers with a sum of 39?
The integers are 11, 13 and 15.
Related Questions
What two negative integers have a sum of -12 and a product of 11?
-11 and -1
What two integers have a sum of -11 and their product is 24?
-8 and -3
Two positive integers have a sum of 17 and a product of 66 What are the integers?
11 and 6 11+6 = 17 11*6 = 66
What integers have a product of 18 and a sum of -11?
29
Find two integers whose product is 24 and who sum is -11?
35
What are the two positive integers that have a sum of 19 and a product of 88?
11 and 8 11+8 = 19 11*8 = 88
The sum of 2 integers is 25 Their product is 154 Name the integers?
11 & 14
What two numbers have a sum of 11 and a product of 24?
8 + 3 = 11 8 x 3 = 24 The two numbers are therefore 8 and 3.
What are Two integers whose product is 18 and whose sum is 11?
2 and 9 2*9 = 18 2+9 = 11
What is the integer of product -26 sum -11?
-15
What is the two integers whose sum is 3 and whose difference is 11?
The two integers are -4 and 7.
What two numbers have a sum of -11 and product of 24?
-8 and -3 have a sum of -11 and product of 24
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