The numbers are 5 and 6.
2 and 9 2*9 = 18 2+9 = 11
-11 and -10
-10 -11
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
The integers are 11, 13 and 15.
-11 and -1
-8 and -3
11 and 6 11+6 = 17 11*6 = 66
29
35
11 and 8 11+8 = 19 11*8 = 88
11 & 14
8 + 3 = 11 8 x 3 = 24 The two numbers are therefore 8 and 3.
2 and 9 2*9 = 18 2+9 = 11
-15
The two integers are -4 and 7.
-8 and -3 have a sum of -11 and product of 24