The factor pairs of 72 are (72,1)(36,2)(24,3)(18,4)(12,6)(9,8)
None of them total 19.
199
43
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
They are: 5 and 14
The sum of two numbers witha difference of two equals forty can be set up and solved this way: x + (x - 2) = 40 2x - 2 = 40 2x = 42 x = 21 x - 2 = 19 The two numbers are 21 and 19.
To solve this problem, we are looking for two numbers that multiply to 150 and add to -19. Letβs break it down: Product of the two numbers: The two numbers should multiply to give 150. Sum of the two numbers: The same two numbers should add up to -19.
199
19
-101
29
79
-19
41
1 and 19
1 and 19
19
1 time 19