1 in 5
Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of randomly selecting the vowel letter 'a' is P(v) = 1/4. Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of randomly selecting a vowel letter is P(v) = 2/5. The probability of randomly selecting a vowel letter from the first word and a vowel letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%
The word 'probability' has 11 letters and 5 of them are vowels (including the 'y'). Therefore the probability of picking a vowel is 5/11.
The answer depends onthe alphabet that you chose,whether or not you consider y to be a vowel,whether or not each letter is equally likely to be chosen (eg not from a bag of scrabble tiles), andwhether or not the choice was random.If a choice was random, from equal numbers of letters from the modern Roman alphabet and y is not considered a vowel then the answer is 5/26.
There are 26 letters and 5 vowels so 5/26.
You have a total of 11 letters in "mathematics" and you have 4 vowels (a,e,a,i) so the probability of drawing a vowel is 4/11. In other words if you were to consider the vowel's to be 1's and the consonants 2's. What is the probability of drawing a "1". There would be 4 1's and 7 2's. It would be 4/11
Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of randomly selecting the vowel letter 'a' is P(v) = 1/4. Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of randomly selecting a vowel letter is P(v) = 2/5. The probability of randomly selecting a vowel letter from the first word and a vowel letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%
The probability for a single random choice, is 6/13.
If the letters of computer are randomly arranged in all possible ways, the probability the word begins with a vowel in five out of 26, or 0.1923. You do not need to consider any other letters, or any permutations or combinations, because you only asked about the first letter.
There are 10 letters in the word "aspiration" and 5 of them are vowels. The probability of a randomly-selected letter being a vowel are 5/10 = 1/2 = 0.50.
"Puzzle" has 6 letters, and 2 of them are vowels. So the odds of choosing a vowel are 2/6, which equals 1/3, which is one-third or 33.33%.
The word 'probability' has 11 letters and 5 of them are vowels (including the 'y'). Therefore the probability of picking a vowel is 5/11.
5/24, or five out of twenty four, or with numbers, five out of infinity
When they choose the letters R, S, T, L & N first they are choosing the most probable letters. When they choose to purchase an I after seeing the NG at the end of a word they are choosing the most probable vowel at that location and able that the vowel may still be used elsewhere.When they purchase the E vowel first the are buying the vowel that is used most. When they guess a H after seeing a three letter word beginning with a T they are not using the letter with the highest probability which would be buying the E to confirm that the word is likely the and if it is not the E is likely used elsewhere.
The probability that a letter picked at random is not a vowel depends on the set of letters you are choosing from. In the English alphabet, there are 21 consonants and 5 vowels, so the probability of picking a consonant is 21/26 or approximately 0.808.
3 in 8, 0.375, if you consider the y as a consonant, 4 in 8, 0.5, if not.
The answer depends onthe alphabet that you chose,whether or not you consider y to be a vowel,whether or not each letter is equally likely to be chosen (eg not from a bag of scrabble tiles), andwhether or not the choice was random.If a choice was random, from equal numbers of letters from the modern Roman alphabet and y is not considered a vowel then the answer is 5/26.
There are 26 letters and 5 vowels so 5/26.