if it convert
I would say they are in standard form, but I would be more likely just to ask you to write a simplified number without using exponents. The terminology can vary, but the following example shows the usual names: 1,023 is in standard form. One thousand twenty-three is in word form. 1000 + 20 + 3 is in expanded form.
We usually say something like "y=ex is the parent function of y=3ex-2+10", so the answer to your question is probably " The child functions of y=ex have the form aebx+c+d."
You can factor this multivariate polynomial (a polynomial with several variables, here x and y), by looking at it as a univariate polynomial in either x or y. This would give you a simple second order equation of the form ax2+bx+c, which you can solve. This will give you 2 solutions, say x1 and x2, and can then factor your polynomial to a(x-x1)(x-x2). In our case: a=8, b=-y and c=-7y2 and the solutions for this equation are x1=y and x2=-7/8*y and this gives us 8x2 - xy -7y2 = 8(x-y)(x+7/8y) = (x-y)(8x+7y)
Let's say you want the standard form of the equation x2 + 10x + y + 20 = 0. x2 + 10x + y + 20 = 0 (add 5 and subtract y to both sides) x2 + 10x + 25 = -y + 5 (form the square to the left, and factor out -1 to the right) (x + 5)2 = -(y - 5) which is in the standard form (x - h)2 = 4p(y - k), where (h, k) = (-5, 5) is the vertex, and 4p = -1 yields p = -1/4, so the parabola opens downward.
The way you wrote it is the standard form.
Do you mean, "the difference between an algorithm that runs in polynomial time, and one that runs in exponential time".First a real quick review. A polynomial is any equation of the formy = cmxm + ... + c2x2 + c1x + c0 ,where ci are constantsAn exponential function is something of the formy = cxThese functions grow much faster than any polynomial function.So, if T(n) describes the runtime of an algorithm as a function of whatever (# of inputs, size of input, etc.)., and T(n) can be bound above by any polynomic function, then we say that algorithm runs in polynomial time.If it can't be bound above by a polynomial function, but can be bound above by an exponential function, we say it runs in exponential time.Note how ugly an exponential algorithm is. By adding one more input, we roughly double (or triple, whatever c is) the run-time.
337,123,421 in standard form is 3.37123421 × 108
There are many things that can be said about a polynomial function if its fourth derivative is zero, but the main thing you can know about this function from this information is that its order is 3 or less. Consider an nth order polynomial with only positive exponents: axn + bxn-1 + ... + cx2 + dx + e As you derive this function, its derivatives will eventually be equal to zero. The number of derivatives that are nonzero before they all become zero can tell you what order the polynomial function was. Consider an example, y = x4. y = x4 y' = 4x3 y'' = 12x2 y''' = 24x y(4) = 24 y(5) = 0 The original polynomial was of order 4, and its derivatives were nonzero up until its fifth derivative. From this, you can generalize to say that any function whose fifth derivative is equal to zero is of order 4 or less. If the function was of higher order than 4, its derivatives would not become zero until later. If the function was of lower order than 4, its fifth derivative would still be zero, but it would not be the first zero-valued derivative. So this experimentation yielded a rule that the first zero-valued derivative is one greater than the order of the polynomial. Your problem states that some polynomial has a fourth derivative that is zero. Our working rule states that this polynomial can be of highest order 3. So, your polynomial can be, at most, of the form: y = ax3 + bx2 + cx + d Letting the constants a through d be any real number (including zero), this general form expresses any polynomial that will satisfy your condition.
Writing a number in standard form simply means to express the number in its 'normal' form. Therefore, your example is written in standard form.
you can say that it is polynomial if that have a exponent
0.10
the exponential form is 10^68 or ten to the 68th power standard form would be 100000000000000000000000000000000000000000000000000000000000000000000
The standard form is expressed as 5,302,014
Writing a number in standard form simply means to express the number in its 'normal' form. Therefore, your example is written in standard form as: 0.015
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if it convert