7x-4=9x+10-14=2xx=-7
x2 - 7x = 8 x2 - 7x - 8 = 0Now find two numbers that multiply to equal -8, and add to equal -7.(1) * (-8) = -8(1) + (-8) = -7(x+1)(x-8) = 0 This is the factored form of x2 - 7x = 8You can then solve the equation if necessary, and get:x = -1 or x = +8
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
7x+3=10 7x=7 {subtract 3 from each side} x=1 {divide each side by 7}
Presumably this is an equation in which the value of x is to be found. 7x+8 = 4x-10 7x-4x = -10-8 3x = -18 x = -6
7x+10=31x so 10=31x-7x or 10 =24x in which case x=10/24 or 5/12
7x2-10x+3=0 (7x-3)(x-1)=0
10
Impossible because the discriminant is less than zero do you mean x2+7x-18? Then if so it is (x+9)(x-2) when factored
y = 3x + 21x2 = 3x(1 + 7x)
When factored it is: (7x+8)(7x-9)
x2+7x-18 = (x+9)(x-2) when factored
The Y intercept of y=7x+10 is 10.
2x = 7x - 10 subtract the 7x from both sides 2x - 7x = -10 -5x = -10 divide both sides by -5 x = 2
7x-4=9x+10-14=2xx=-7
If you mean: 7x+91 then it can be factored to 7(x+13)
One is a polynomial and the other is an equationA polynomial can (possibly) be factoredAn equation can (possibly) be factored and then solvedFactoring:xx+7x-30(x+10)(x-3)Solving:xx+7x-30=0(x+10)(x-3)=0Either (x+10) and/or (x-3) is equal to threex+10=0x=-10x-3=0x=3