If you mean: x2+6x+8 then it is (x+4)(x+2) when factored
"(x - 5)(x - 2)"
(x - 8)(x - 6)
x2-2x-15 = (x+3)(x-5) when factored
It is: (x+4)(x-2) when factored
3x2 - 10x - 8 = (3x + 2) (x - 4)
It is (x-1)(x-8) when factored
64-x2 = (8-x)(8+x) when factored
x2-6x+8 = (x-2)(x-4) when factored
If you mean: x2+6x+8 then it is (x+4)(x+2) when factored
If that is + 192 then divide all terms by 3 and it is (x+8)(x+8) when factored
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
-7
"(x - 5)(x - 2)"
3 x 5 x 5 = 75
x2 - 64 can be written as x2 - 82, which is of the form of a2 - b2.And a2 - b2 is factored as (a-b)(a+b).Therefore, x2 - 64 is factored as (x+8)(x-8).
74