Usually the width
You would multiply the length with the width so 5 feet can be the width and 3 feet can be the length. 5x3=15 s/f
Width is 5.
1+ square root of 5 over 2 not positive
They are: 3 inches and 5 inches respectively
Area, A, is two dimensional so has a width and length, say. You have three dimensions. A three-dimensional entity has a width, length, and height, represented by V (for volume). The size of your volume entity is 5 x 4 x 8 inches = 160 cubic inches.
5' in width, 8-10' in length.
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
Rectangular perimeter = 2(Length + Width) Width = a Length = a+5 Then, 84 = 2(a+a+5) 42 = 2a+5 (42-5)/2 = a = 18.5m = Width Length = a+5 = 23.5m
OK so we have two formulas: Length = width + 5 (since legth is 5 more than width) length + width + length + width = perimeter= 82 (form. for perm.) so we can replace every instance of "length" with "width + 5" since they are the same. width + 5 + width + width + 5 + width = 82 4xwidth + 10 = 82 4X width = 72 width = 23 so now go back and replace "width" with 23. length = 23 + 5 length = 28 There you go.
You would multiply the length with the width so 5 feet can be the width and 3 feet can be the length. 5x3=15 s/f
The length of the length will be 5 and the width will be 25.
width=5 length=12
25 feet Pythagorean theorem says length of diagonal is square root of (width squared plus length squared). This is a 3-4-5 ratio right triangle
38'' length 14''heigth 5''width
The normal size of a car slot is 5 meters in length and 2 meters in width.
3in x 5in is the standard size. Occasionally 5 x 7
5 inches length and 3 inch width -Matt Speilman