25 feet
Pythagorean theorem says length of diagonal is square root of (width squared plus length squared). This is a 3-4-5 ratio right triangle
length of diagonal of 20 of a 20 feet and 15 width.
Diagonal = 18.867 feet.
18.9 feet
4 feet high by 8 feet wide = diagonal of 107.28 inches.
The diagonal can be found by taking length^2+width^2=diagonal^2 13^2=x^2+(x+7)^2 169 = x2 + x2 + 14x + 49 120 = 2x2 + 14x x2 + 7x - 60 = 0 now just factor, and you have the answer. It's the positive x value.
length of diagonal of 20 of a 20 feet and 15 width.
The length of the diagonal is about 16.03 feet.
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
Diagonal = 18.867 feet.
A square with an area of 80 acres has a length and width of 1,867 feet. The diagonal length of the square is 2,640 feet.
18.9 feet
18.9 feet
On any rectangular area: Area = (Length) x (Width) Length = (Area) / Width) Length = (800) / (20) = 40 feet
the tennis court is about 78 feet long and 27 feet width the tennis court is about 78 feet long and 27 feet width
94 feet by 50 feet
4 feet high by 8 feet wide = diagonal of 107.28 inches.
The diagonal can be found by taking length^2+width^2=diagonal^2 13^2=x^2+(x+7)^2 169 = x2 + x2 + 14x + 49 120 = 2x2 + 14x x2 + 7x - 60 = 0 now just factor, and you have the answer. It's the positive x value.