Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. We are, therefore unable to determine what exactly the question is about and so cannot give a proper answer to your question. Please edit your question to include words for symbols and resubmit.
-2
1
Assuming y=2x+5 and x=2y-15y=2x+5 (1)x=2y-15 (2)Substitute y=2x+5 into (2):x=2(2x+5)-15x=4x+10-150=3x+10-150=3x-55=3x5/3=x (x=5/3)Substitute x=5/3 into y=2x+5:y=2(5/3)+5y=10/3+5y=25/3x=5/3, y=25/3
x - y = 5 + 2x + y = 7 => 3x + 0 = 12 => 3x = 12 => 3x/3 = 12/3 => x=4 x-y=5 2x+y=7 =>4-y=5 =>2(4)+y=7 =>y=4-5 =>8+y=7 =>y=-1 =>y=-1 So, the answer would be x=4 and y=-1
3x-y to the third becomes (x+x)+x-y*y*y the question is (3x-y)3
-2
3x - y = 0 5y = 15 5y = 15 Divide by '5' on both sides Hence y = 3 Substitute for 'y' in the first equation./ 3x - 3 = 0 3x = 3 Divide both sides by ;3; x = 1 So in ( x,y) form the answer is ( 1,3).
2. If x=5 & y =3 then: 3x + 2y = 3 x 5 + 2 x 3 = 15 + 6 = 21 2x + 3y = 2 x 5 + 3 x 3 = 10 + 9 = 19 ⇒ 3x+2y exceeds 2x+3y by 21 - 19 = 2. Alternatively: 3x+2y exceeds 2x+3y by: (3x+2y) - (2x + 3y) = 3x + 2y - 2x - 3y = x - y If x=5 & y=3 then this becomes: x - y = 5 - 3 = 2
-8
1
Where is y in the first equation, you put its equivalent (=) -3x + 11 The first equation is then transformed into: 3x + 2*(-3x + 11) = 7. Then you get: 3x + (-6x) + 2*11 = 7 <=> -3x + 22 = 7 <=> 22 - 7 = 3x <=> 3x = 15 <=> x = 15/3 <=> x = 5. Then you substitute the x in the second equation by its equivalent so, (x = 5) y = -3*x + 11 <=> y = -3*5 + 11 <=> y = -15 + 11 <=> y = -4. x = 5. y = -4.
Assuming y=2x+5 and x=2y-15y=2x+5 (1)x=2y-15 (2)Substitute y=2x+5 into (2):x=2(2x+5)-15x=4x+10-150=3x+10-150=3x-55=3x5/3=x (x=5/3)Substitute x=5/3 into y=2x+5:y=2(5/3)+5y=10/3+5y=25/3x=5/3, y=25/3
3x - y = -1 x = -2 3(-2) -y = -1 -6 - y = -1 -y = 5 y = -5
6
x - y = 5 + 2x + y = 7 => 3x + 0 = 12 => 3x = 12 => 3x/3 = 12/3 => x=4 x-y=5 2x+y=7 =>4-y=5 =>2(4)+y=7 =>y=4-5 =>8+y=7 =>y=-1 =>y=-1 So, the answer would be x=4 and y=-1
If you mean: y -7 = 3(x -4) then y = 3x -5
3x-y to the third becomes (x+x)+x-y*y*y the question is (3x-y)3