In the expression 3x + y, when x = 3 and y = 5, we substitute these values into the expression: 3(3) + 5. This simplifies to 9 + 5, which equals 14. Therefore, when x = 3 and y = 5, the value of 3x + y is 14.
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Assuming y=2x+5 and x=2y-15y=2x+5 (1)x=2y-15 (2)Substitute y=2x+5 into (2):x=2(2x+5)-15x=4x+10-150=3x+10-150=3x-55=3x5/3=x (x=5/3)Substitute x=5/3 into y=2x+5:y=2(5/3)+5y=10/3+5y=25/3x=5/3, y=25/3
x - y = 5 + 2x + y = 7 => 3x + 0 = 12 => 3x = 12 => 3x/3 = 12/3 => x=4 x-y=5 2x+y=7 =>4-y=5 =>2(4)+y=7 =>y=4-5 =>8+y=7 =>y=-1 =>y=-1 So, the answer would be x=4 and y=-1
3x-y to the third becomes (x+x)+x-y*y*y the question is (3x-y)3
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3x - y = 0 5y = 15 5y = 15 Divide by '5' on both sides Hence y = 3 Substitute for 'y' in the first equation./ 3x - 3 = 0 3x = 3 Divide both sides by ;3; x = 1 So in ( x,y) form the answer is ( 1,3).
2. If x=5 & y =3 then: 3x + 2y = 3 x 5 + 2 x 3 = 15 + 6 = 21 2x + 3y = 2 x 5 + 3 x 3 = 10 + 9 = 19 ⇒ 3x+2y exceeds 2x+3y by 21 - 19 = 2. Alternatively: 3x+2y exceeds 2x+3y by: (3x+2y) - (2x + 3y) = 3x + 2y - 2x - 3y = x - y If x=5 & y=3 then this becomes: x - y = 5 - 3 = 2
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Where is y in the first equation, you put its equivalent (=) -3x + 11 The first equation is then transformed into: 3x + 2*(-3x + 11) = 7. Then you get: 3x + (-6x) + 2*11 = 7 <=> -3x + 22 = 7 <=> 22 - 7 = 3x <=> 3x = 15 <=> x = 15/3 <=> x = 5. Then you substitute the x in the second equation by its equivalent so, (x = 5) y = -3*x + 11 <=> y = -3*5 + 11 <=> y = -15 + 11 <=> y = -4. x = 5. y = -4.
Assuming y=2x+5 and x=2y-15y=2x+5 (1)x=2y-15 (2)Substitute y=2x+5 into (2):x=2(2x+5)-15x=4x+10-150=3x+10-150=3x-55=3x5/3=x (x=5/3)Substitute x=5/3 into y=2x+5:y=2(5/3)+5y=10/3+5y=25/3x=5/3, y=25/3
3x - y = -1 x = -2 3(-2) -y = -1 -6 - y = -1 -y = 5 y = -5
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x - y = 5 + 2x + y = 7 => 3x + 0 = 12 => 3x = 12 => 3x/3 = 12/3 => x=4 x-y=5 2x+y=7 =>4-y=5 =>2(4)+y=7 =>y=4-5 =>8+y=7 =>y=-1 =>y=-1 So, the answer would be x=4 and y=-1
If you mean: y -7 = 3(x -4) then y = 3x -5
3x-y to the third becomes (x+x)+x-y*y*y the question is (3x-y)3