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If the coefficient of the highest power of a variable of interest is negative.
In a mathematical equation, the constant is defined as a term in the equation that only includes a real number. Since a negative number is a real number, then yes, a negative number can be considered a constant. For example, in the equation 6x -2... -2 would be the constant because it is a term that contains only the real number (-2).
No, they do not. If the first term is negative, they always decrease.
a^(2)- 2ab - 15b^(2) When the first term has a coefficient of '1' (a^(2)), then look at the third term. It is '15'. So we need two numbers that multiply to '15' and 'add/subtract'to '2'. They are 3. & 5. So writing up our brackets ( a 5b)(a 3b) Which signs??? We note from the quadraic , that '15' is negative(-) . So the brackets need one positive(+) and one negative(-) Since the middle term is also negative(-) , then the larger numerical number takes the negative. Hence ( a - 5b)(a + 3b) Done!!!!
If it's inside the brackets it means that it belongs to that specific term, but if it was outside the brackets, it means that every term inside the brackets goes out with opossite sign. For example: [ -5x + 6y ] = -5x + 6y , the negative is only for 5x, but if you had - [ -5x + 6y] = 5x - 6y , every term inside the bracket goes out with opossite sign.