y = 5x - 2
This follows the general equation for a straight line y = mx + c.
Where 'm' is the slope/gradient and 'c' is the y-intercept.
At the point the line crosses the y-axis , then x = 0
Hence
y = 5(0) - 2
y = -2 is the point the line intercept the y-axis.
5x2 - 136 = 44 5x2 - 136 + 136 = 44 + 136 5x2 = 180 5x2/5 = 180/5 x2 = 36 √x2 = √36 x = ±6
False
5x2 - 20 = 0x2 - 4 = 0x2 = 4x = +2 and -2
I dont see any related links or files that I need to follow as indicated by your question. the general form of 5x2 - 20x = 15 is... 5x2 - 20x - 15 = 0 ax2 + bx + c = 0
its not...
In one word 'NO' Since it is and 'x^(2)' term, this will make a parabolic curve, not linear (straight line).
5x2=10...take 5 two times..5+5=10
No.
5x^(2) = 11 Divide both saudes by 5' Hence x^(2) = 11/5 Square root both sides x = +/-sqrt (11/5) Or x = +/-sqrt(2.2) This would normally by left in 'surd' form, because the answer is an IRRATIONAL number; the decimals go to inifinity!!!!! However, per calculator x = +/- 1.483239697.....
5x2 - 136 = 44 5x2 - 136 + 136 = 44 + 136 5x2 = 180 5x2/5 = 180/5 x2 = 36 √x2 = √36 x = ±6
5x2-136 = 24 5x2 = 24+136 5x2 = 160 x2 = 32 x = the square root of 32
5x2y = 3x - 6y 5x2y + 6y = 3x y(5x2 + 6) = 3x y = (3x)/(5x2 + 6) This is a rational function.
5x2 = 3 then x2 = 3/5 so that x = sqrt(3/5) = ± 0.7746
1) 5x2-55=90 +55 +55 2) 10x=145 /10 /10 x=14.5
The discriminant is 385.
for x = -2: x2 = 4, -5x2 = -20; 3x = -6 giving -20 - (-6) = - 20 + 6 = -14.
5x^(2) + 2x - 4 = 2x^(2) Hence 3x^(2) + 2x - 4 = 0 Now apply the Quadratic Equation. x = { - 2 +/- sqrt[2^(2) - 4(3)(-4)]} / 2(3) x = {-2 +/- sqrt[4 + 48]} / 6 x = { -2 +/- sqrt(50_] / 6 x = { -2 +/-5sqrt(2)} / 6 x = (-2 - 5sqrt(2))/ 6 & x = (-2 + 5sqrt(2))/ 6 Since the square root of '2' is an Irrational Number. (decimals go to infinity, the answer is left in 'surd' form .