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Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
It is x = +/- 2 depending on whether the second term in the equation is -12x or +12x.
Yes and this will happen when the discriminant of a quadratic equation is less than zero meaning it has no real roots.
Line of symmetry: x = 3
If a quadratic function has the points (-4,0) and (14,0), what is equation of the axis of symmetry?
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
y = 2x + 2 + 4x+ 2 = 6x + 4 This is NOT a symmetric function and so there is no axis of symmetry.
It is x = +/- 2 depending on whether the second term in the equation is -12x or +12x.
y-axis
-1
Yes and this will happen when the discriminant of a quadratic equation is less than zero meaning it has no real roots.
An even function is a function that creates symmetry across the y-axis. An odd function is a function that creates origin symmetry.
X=-b/2a
It is the axis of symmetry.