X=-b/2a
12 x 5 = 60
Its extremum is on its axis of symmetry.
The x-axis is the horizontal axis on a graph. The y-axis is the vertical axis on a graph.
To find the y-intercept from a graph - look at where the graph of the line intersects the y-axis. The point at where the graph of the line crosses the y-axis will be the y-intercept with the coordinates of (0,y) The point at which the line cuts the y – axis is called as y – intercept.You can locate the point by seeing the graph.Note:If you are given a linear equation say ax + by + c = 0Now if we plug x = 0 in the given equation we will get the y – intercept.y = -c/bIf the given equation is of the form y = mx + bb is the y – intercept of the line. Source: www.icoachmath.com
b is where the line on the graph intercepts the y axis ( The vertical Line ) in a slope intercept equation
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
If a quadratic function has the points (-4,0) and (14,0), what is equation of the axis of symmetry?
y = x2 + 8x - 7 a = 1, b = 8, c = -7 the equation of the axis of symmetry: x = -b/2a x = -8/(2*1) = -4
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
It is the axis of symmetry.
y = 2x2 + 3x + 6 Since a > 0 (a = 2, b = 3, c = 6) the graph opens upward. The coordinates of the vertex are (-b/2a, f(-b/2a)) = (- 0.75, 4.875). The equation of the axis of symmetry is x = -0.75.
-1
I regret that I can see no function shown.
Then that part of the graph is below the x-axis.
x=constant
An Axis of Symmetry is any line along which any Graph, group of graphs, or other shape may be divided into two symmetrical pieces which are perfect mirror images of one another.