That depends on the equation. In general, you'll try to isolate the variable, by using operations (on both sides of the equation) that get rid of anything other than the variable, on the side the variable is on.
If a statement includes an "equals" sign ( = ) then the statement is an equation. By the way . . . it may or may not be a true statement. "10 equals 120" is not true.
No.
you have to focus on your unit and try your best by the way its your teacher
Please note that in general, if you have ONE equation with TWO or more variables, there is not a unique solution. You can assign an arbitrary value for "a", replace it, then calculate what would be the corresponding value of "b". Or, probably even better, you can solve for "b" in terms of "a". Then you can assign any value to "a", and calculate the corresponding value for "b". To actually solve for "b", first solve for b2 in the usual way, that is, manipulate the equation until b2 is on the left, everything else on the right. Then take the square root on each side.
It depends on which variable you wish to solve for.
Take the square root of both sides of the equation
You cannot go beyond x = k unless you know the value of k. And in that case, the equation is solved so there is nothing further to do!
Without an equality sign the given expression can't be considered to be an equation.
do you mean, x2 = n?? Take the square root.
The equation cannot be "solved", nor can it be simplified in any significant way. It is the equation of a line and the coordinates of any one of the infinite number of points on that line will be a solution to the equation.
If x squared equals n, then x is the square root of n.
That depends on the equation. In general, you'll try to isolate the variable, by using operations (on both sides of the equation) that get rid of anything other than the variable, on the side the variable is on.
The easiest way to solve this system of equations is to solve for a variable in one of the equations. In the second equation, y = 3x. This can be substituted into the first equation: y = -4x - 7; 3x = = -4x - 7; 7x = -7; x = -1. Since we have determined that x equals -1, we can then substitute -1 into either equation to find our corresponding y-value. Thus: y = 3x; y = 3(-1) y = -3. Thus, the solution to this system of equations is (-1, -3).
You solve the equation the same way as you would any other equation. Whether the variable is a fraction or otherwise will only become clear once you solve the equation. In other words, you don't initially KNOW whether the solution will be a fraction or not.
I'm going to solve [ 2b = 10 ] for you, but I'm not going to do it in the best way.The best way is for you to make a date with your teacher to sit down and reviewsome of this stuff, so that you know how to do it.The way I'm going to do it, you'll have the solution to [ 2b = 10 ], but there will bethree problems with it:-- Nobody needs that information.-- You won't learn anything.-- If you need to solve [ 3d = 15 ] tomorrow, you'll be just as clueless as you are today.Here's the solution, and the method of finding it:1). Write down the equation :2b = 102). Divide each side of the equation by 2 :b = 5
You could multiply the first equation by 3 and the second by -5 and eliminate the x... OR you could multiply the first equation by 7 and the second by 10 and eliminate the y. Either way works.