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Which of the following are solutions to the quadratic equation below Check all that apply. x2 plus 7x - 8 0?
Wiki User
∙ 7y ago
To solve the equation x^2 + 7x - 80, you would get x = 6.105 and x = -13.105, I believe.
Wiki User
∙ 7y ago
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When solving a rational equation why is it necessary to perform a check?
It is important to check your answers to make sure that it doesn't give a zero denominator in the original equation. When we multiply both sides of an equation by the LCM the result might have solutions that are not solutions of the original equation. We have to check possible solutions in the original equation to make sure that the denominator does not equal zero. There is also the possibility that calculation errors were made in solving.
How do you find the solution of a quadratic equation graphically?
You write the equation in such a way that you have zero on the right side. Then you graph the expression on the left side of the equal sign, and check where it touches the x-axis. Note that this method works for most common equations.
What is the extraneous solution to w equals sqrt 7w?
An "extraneous solution" is not a characteristic of an equation, but has to do with the methods used to solve it. Typically, if you square both sides of the equation, and solve the resulting equation, you might get additional solutions that are not part of the original equation. Just do this, and check each of the solutions, whether it satisfies the original equation. If one of them doesn't, it is an "extraneous" solution introduced by the squaring.
What reasoning and explanations can be used when solving radical equations?
The basic method is the same as for other types of equations: you need to isolate the variable ("x", or whatever variable you need to solve for). In the case of radical equations, it often helps to square both sides of the equation, to get rid of the radical. You may need to rearrange the equation before squaring. It is important to note that when you do this (square both sides), the new equation may have solutions which are NOT part of the original equation. Such solutions are known as "extraneous" solutions. Here is a simple example (without radicals): x = 5 (has one solution, namely, 5) Squaring both sides: x squared = 25 (has two solutions, namely 5, and -5). To protect against this situation, make sure you check each "solution" of the modified equation against the original equation, and reject the solutions that don't satisfy it.
Solve y 3x2 6x-9 using the quadratic formula?
To find the zeros of this quadratic function, y= 3x^2 + 6x - 9, we must equal y to 0. So we have the quadratic equation: 3x^2+6x-9 = 0, where a = 3, b = 6, and c = -9 The quadratic formula: x = [-b ± √(b^2 - 4ac)]/(2a) substitute what you know into this formula; x = [-6 ± √(6^2 - 4 x 3 x -9)]/(2 x 3) x = [-6 ± √(36 +108)]/6 x = (-6 ± √144)/6 x = (-6 ± 12)/6 Simplify: mulyiply by 1/6 both the numerator and the denominator; x = -1 ± 2 x = -1 + 2 or x = -1 - 2 x = 1 or x = -3 So solutions are -3 and 1. If you check the answers by plugging them into the equation, you will see that they work.
How do you check whether the equation 7x2x is quadratic?
If it doesn't have an equal sign, then it's an expression, not an equation. The expression 7x2x is quadratic, because it equals 14x², and something is quadratic if it contains the squared exponent ².
How do you check the quadratic formula?
Substitute your answer in the original equation and see if it works out.
When solving a rational equation why is it necessary to perform a check?
It is important to check your answers to make sure that it doesn't give a zero denominator in the original equation. When we multiply both sides of an equation by the LCM the result might have solutions that are not solutions of the original equation. We have to check possible solutions in the original equation to make sure that the denominator does not equal zero. There is also the possibility that calculation errors were made in solving.
How would you use a T-table to determine 3 solutions to this equation 4x - 2y equals 8?
A quadratic equation is defined as an equation in which one or more of the terms ... In Geometry, we will concentrate on the graphical solutions to these systems. ... You can use the same table of values and simply find the y values for the straight line. ... Check (5,3) y = x2 - 4x - 2 3 = 52 - 4(5) - 2 3 = 3 check, y = x - 2 3 = 5 - 2
In general when solving a radical equation should you first isolate the radical and then both sides?
It often helps to isolate the radical, and then square both sides. Beware of extraneous solutions - the new equation may have solutions that are not part of the solutions of the original equation, so you definitely need to check any purported solutions with the original equation.
How do you find the solution of a quadratic equation graphically?
You write the equation in such a way that you have zero on the right side. Then you graph the expression on the left side of the equal sign, and check where it touches the x-axis. Note that this method works for most common equations.
What is 6t squared plus 17t plus 12?
-4/3 and -3/2 To solve this, you must find the two factors that multiply to equal that trinomial (or use the quadratic equation) that trinomial can be rewritten as (3t + 4)(2t + 3) *check this first. It will prove that it is correct* Then, find the values of t when the equation equals 0 and you will see that the solutions are -4/3 and -3/2
What is the extraneous solution to w equals sqrt 7w?
An "extraneous solution" is not a characteristic of an equation, but has to do with the methods used to solve it. Typically, if you square both sides of the equation, and solve the resulting equation, you might get additional solutions that are not part of the original equation. Just do this, and check each of the solutions, whether it satisfies the original equation. If one of them doesn't, it is an "extraneous" solution introduced by the squaring.
The graph of a a certain quadratic function has no x-intercepts. Which of the following are possible values for the discriminant check all that apply. (APEX)?
-7,-25
A2 plus 0.7a - 0.1 equals 0?
Presumably this is a quadratic equation question in the form of: a2+0.7a-0.1 = 0 Using the quadratic equation formula will give you: (a+0.8216990566)(a-0.1216990556) = 0 Therefore: a = -0.8216990566 or a = 0.1216990566 Check that your answer is correct by multiplying out the brackets you should end up with: a2+0.7a-0.1 = 0
What are the steps to solving a radical equation?
Details may vary depending on the equation. Quite often, you have to square both sides of the equation, to get rid of the radical sign. It may be necessary to rearrange the equation before doing this, after doing this, or both. Squaring both sides of the equation may introduce "extraneous" roots (solutions), that is, solutions that are not part of the original equation, so you have to check each solution of the second equation, to see whether it is also a solution of the first equation.
Why is it necessary to check for extraneous solutions in radical equations?
1) When solving radical equations, it is often convenient to square both sides of the equation. 2) When doing this, extraneous solutions may be introduced - the new equation may have solutions that are not solutions of the original equation. Here is a simple example (without radicals): The equation x = 5 has exactly one solution (if you replace x with 5, the equation is true, for other values, it isn't). If you square both sides, you get: x2 = 25 which also has the solution x = 5. However, it also has the extraneous solution x = -5, which is not a solution to the original equation.
