Here's the graph:
In general, quadratic equations have graphs that are parabolas. The quadratic formula tells us how to find the roots of a quadratic equations. If those roots are real, they are the x intercepts of the parabola.
The given equation is not that of a parabola.
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To determine the equation of a parabola with a vertex at the point (5, -3), we can use the vertex form of a parabola's equation: (y = a(x - h)^2 + k), where (h, k) is the vertex. Substituting in the vertex coordinates, we have (y = a(x - 5)^2 - 3). The value of "a" will determine the direction and width of the parabola, but any equation in this form with varying "a" values could represent the parabola.
One way would be to graph the two equations: the parabola y = x² + 4x + 3, and the straight line y = 2x + 6. The two points where the straight line intersects the parabola are the solutions. The 2 solution points are (1,8) and (-3,0)
Equations are not linear when they are quadratic equations which are graphed in the form of a parabola
Descartes used the parabola to illustrate algebraic equations. He put these equations on a visible plane using the Cartesian coordinate system and they sometimes took the shape of a "u" curve, or a parabola.
the first number out in front you pig
quadratics are used for things like satellite dishes... there are more uses but that's only a basic one =) we are doing a project in math that requires quadratic equations. we make a parabola and put aluminum (or any other reflector) inside the parabola. we make a stick to put in the middle of the parabola to make a focus. we put the marshmellow on the focus and put the parabola in the sunlight. If done right then the marshmellow should heat up! cool huh?
Go study
The focus of a parabola is a fixed point that lies on the axis of the parabola "p" units from the vertex. It can be found by the parabola equations in standard form: (x-h)^2=4p(y-k) or (y-k)^2=4p(x-h) depending on the shape of the parabola. The vertex is defined by (h,k). Solve for p and count that many units from the vertex in the direction away from the directrix. (your focus should be inside the curve of your parabola)
A parabola looks like a frowning face :( or a smiling face :) The type of equation that would give you a parabola is called a Quadratic equation. Quadratic equations have x^2 as the highest exponent in the equation. ex: x squared + 2x + 1
In general, quadratic equations have graphs that are parabolas. The quadratic formula tells us how to find the roots of a quadratic equations. If those roots are real, they are the x intercepts of the parabola.
you didn't put any equations, but the answer probably begins with y= (x-4)^2+1
The given equation is not that of a parabola.
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