the first number out in front you pig
By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.
Quadratic equation: 9x2-21x+12.25 = 0 Area: 36.75 square cm
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
length 14cm, width 2cm This is worked out by finding the following equations: perimeter = 16 x width length = width + 12 Then working out 16 x width = 2 x (width + 12) + 2 x width -> 14 x width = 2 x (width + 12) -> 14 x width = 2 x width + 24 -> 12 x width = 24 -> width = 2cm Since lendth = width + 12, length = 14cm
You need to solve the two equations P = perimeter A = area B = width H = height P = 2B + 2H A = BH H = A/B P = 2B + 2A/B P = (2B^2 + 2A)/B 2B^2 -PB +2A = 0 use quadratic formula B = (P +/- SQRT(P^2-16A))/4 ONE ROOT IS B, the other is H
By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.
MM is millimeter. Determines the width of the piece. The watch band is 14mm in width.
The width of the rollers and distance they are apart.
Three dimensions: Height Width Length
Quadratic equation: 9x2-21x+12.25 = 0 Area: 36.75 square cm
bus width
The width of the rollers and distance they are apart.
the equations tell you what the surface area of somthing is
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
yes
Example:- What are the dimensions of a rectangle when its length is greater than its width by 4 cm and has an area of 96 square cm? Let the length be x+4 and the width x: length*width = area (x+4)*x = 96 => x2+4x-96 = 0 => (x+12)(x-8) = 0 when factored So: x = -12 or x = 8 the dimensions can't be negative Solution: length = 12 cm and width = 8 cm Check: 12*8 = 96 square cm
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