the first number out in front you pig
A quadratic equation in vertex form is expressed as ( y = a(x - h)^2 + k ), where ((h, k)) is the vertex of the parabola. For a parabola with vertex at ((11, -6)), the equation becomes ( y = a(x - 11)^2 - 6 ). The value of (a) determines the direction and width of the parabola. Without additional information about the parabola's shape, (a) can be any non-zero constant.
To rewrite the equation of a parabola in standard form, you need to express it as ( y = a(x - h)^2 + k ) for a vertically oriented parabola or ( x = a(y - k)^2 + h ) for a horizontally oriented parabola. Here, ( (h, k) ) represents the vertex of the parabola, and ( a ) determines its direction and width. You can achieve this by completing the square on the quadratic expression.
In a quadratic equation of the form (y = ax^2 + bx + c), the value of (a) determines the width of the parabola. If (|a|) is greater than 1, the parabola is narrower, indicating that it opens more steeply. Conversely, if (|a|) is less than 1, the parabola is wider, meaning it opens more gently. The sign of (a) also affects the direction of the opening: positive values open upwards, while negative values open downwards.
In the standard form of a quadratic equation ( y = ax^2 + bx + c ), the value of ( a ) determines the direction and the shape of the graph. If ( a > 0 ), the parabola opens upwards, while if ( a < 0 ), it opens downwards. Additionally, the absolute value of ( a ) affects the width of the parabola: larger values of ( |a| ) result in a narrower graph, while smaller values lead to a wider graph.
The equation of a parabola with its vertex at the point (-36, k) can be expressed in the vertex form as ( y = a(x + 36)^2 + k ), where ( a ) determines the direction and width of the parabola. If the vertex is at (-36), the x-coordinate is fixed, but the y-coordinate ( k ) can vary depending on the specific position of the vertex. If you'd like a specific example, assuming ( k = 0 ) and ( a = 1 ), the equation would be ( y = (x + 36)^2 ).
By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.
MM is millimeter. Determines the width of the piece. The watch band is 14mm in width.
The width of the rollers and distance they are apart.
Three dimensions: Height Width Length
Quadratic equation: 9x2-21x+12.25 = 0 Area: 36.75 square cm
The width of the rollers and distance they are apart.
bus width
the equations tell you what the surface area of somthing is
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
yes
Example:- What are the dimensions of a rectangle when its length is greater than its width by 4 cm and has an area of 96 square cm? Let the length be x+4 and the width x: length*width = area (x+4)*x = 96 => x2+4x-96 = 0 => (x+12)(x-8) = 0 when factored So: x = -12 or x = 8 the dimensions can't be negative Solution: length = 12 cm and width = 8 cm Check: 12*8 = 96 square cm
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