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How do you find the length and width of a rectangle when given the area and perimeter?
By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.
What is the quadratic equation and area of a rectangle when its length is 7 cm greater than its width which is 3x cm?
Quadratic equation: 9x2-21x+12.25 = 0 Area: 36.75 square cm
The Perimeter of a rectangle is 56cm The length is 2cm less than twice the width find the length and width?
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
The perimeter of a rectangle is 16 times the width the length is 12cm more than the width what are the length and width of the rectangle?
length 14cm, width 2cm This is worked out by finding the following equations: perimeter = 16 x width length = width + 12 Then working out 16 x width = 2 x (width + 12) + 2 x width -> 14 x width = 2 x (width + 12) -> 14 x width = 2 x width + 24 -> 12 x width = 24 -> width = 2cm Since lendth = width + 12, length = 14cm
How do you find the width of a rectangle given perimeter and area?
You need to solve the two equations P = perimeter A = area B = width H = height P = 2B + 2H A = BH H = A/B P = 2B + 2A/B P = (2B^2 + 2A)/B 2B^2 -PB +2A = 0 use quadratic formula B = (P +/- SQRT(P^2-16A))/4 ONE ROOT IS B, the other is H
