The nth term is: 4n
They are increasing by increments of 4 8 16 32 .... etc
A single number, such as 8163264, does not form a sequence.
The following is the answer.
Which of the following equations could be used to solve for the tenth term of the following sequence?15, 13, 11, 9, ...
The sequence is neither arithmetic nor geometric.
If you mean 3, 6, 9, 12 then the nth term is 3n
Each term is double the previous term and so the next term will be 64
The rule that generates the sequence is Un = 9 + 2n (for n = 1, 2, ...
They are increasing by increments of 4 8 16 32 .... etc
N= term number, your equation would be: 2N+2
Benjamin is using counters that are normally circular in shape so he will find it difficult to create rectangular shapes so it follows that an algebraic expression is not possible.
According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways - some simple, some complicated but all equally valid.So, one possible solution to the question isT(n) = (n4 - 6*n3 + 23*n2 - 18*n + 24)/12 for n = 1, 2, 3, ...
No. It is a sequence for which the rule is a quadratic expression.
sequence
Template Sequence
Template Sequence
because it is nothing