The nth term is: 4n
They are increasing by increments of 4 8 16 32 .... etc
A single number, such as 8163264, does not form a sequence.
Which of the following equations could be used to solve for the tenth term of the following sequence?15, 13, 11, 9, ...
The following is the answer.
The sequence is neither arithmetic nor geometric.
If you mean 3, 6, 9, 12 then the nth term is 3n
Each term is double the previous term and so the next term will be 64
The algebraic expression for the given series of numbers is "2n + 9", where n represents the position of the term.
They are increasing by increments of 4 8 16 32 .... etc
N= term number, your equation would be: 2N+2
Benjamin is using counters that are normally circular in shape so he will find it difficult to create rectangular shapes so it follows that an algebraic expression is not possible.
According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways - some simple, some complicated but all equally valid.So, one possible solution to the question isT(n) = (n4 - 6*n3 + 23*n2 - 18*n + 24)/12 for n = 1, 2, 3, ...
No. It is a sequence for which the rule is a quadratic expression.
In an algebraic sequence, that would mean n + 5.
sequence
Template Sequence
because it is nothing