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Q: Which ordered pair is a solution of the equation 4x 2y 16?

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7-4-14

4x-2y=16 has the solution points (0,-8) and (4, 0) at the coordinate axes, and wherever y= 4(x-4).

Without an equality sign the given terms can't be considered to be a straight line equation and so therefore no solution is possible.

2y = 4x - 16 5y = 4x + 8 Subtract the first equation from the second: 3y = 24 so that y = 8 Substitute this into the first equation: 16 = 4x - 16 ie 32 = 4x so that x = 8 So the solution is (8, 8)

y = (x + 2)2 andy = (2x)2(x-2)2 + (y-16)2 = 0

16 = 16 is an identity, not an equation. An identity does not have solutions.

The center of the circle is at (-7, 5)

-4 and 4

There is only one solution to that equation. It's . . . . . x = -16

If you mean: -6n-2n = 16 then -8n = 16 and the solution to the equation is n = -2

(x+7)2+(y+5)2 = 16 Centre of circle: (-7, -5) Radius: 4

Without an equality sign the given expression is not an equation and so therefore no solution is possible.

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