Without an equality sign the given terms can't be considered to be a straight line equation and so therefore no solution is possible.
7-4-14
To find the solution to the system of equations ( y = 7x + 2 ) and ( y = 9x - 14 ), set the equations equal to each other: ( 7x + 2 = 9x - 14 ). Solving for ( x ), we get ( 16 = 2x ) or ( x = 8 ). Substituting ( x = 8 ) into either equation gives ( y = 58 ). Thus, the solution is the ordered pair ( (8, 58) ).
(x+7)2+(y+5)2 = 16 Centre of circle: (-7, -5) Radius: 4
If you mean 10+2y = 16 then the solution is y = 3
No.
7-4-14
Without any plus or minus signs or an equality sign the given terms can't be considered to be an equation.
16
4x-2y=16 has the solution points (0,-8) and (4, 0) at the coordinate axes, and wherever y= 4(x-4).
y = (x + 2)2 andy = (2x)2(x-2)2 + (y-16)2 = 0
The center of the circle is at (-7, 5)
2y = 4x - 16 5y = 4x + 8 Subtract the first equation from the second: 3y = 24 so that y = 8 Substitute this into the first equation: 16 = 4x - 16 ie 32 = 4x so that x = 8 So the solution is (8, 8)
(x+7)2+(y+5)2 = 16 Centre of circle: (-7, -5) Radius: 4
The solutions are: x = -2 and y = 4
If you mean 10+2y = 16 then the solution is y = 3
a = 16
There is no solution to the equation 32'9 and 11 16 plus 32'9 and 11 16.