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Without an equality sign the given terms can't be considered to be a straight line equation and so therefore no solution is possible.

Q: Which ordered pair is the solution for 3x plus 4y 16?

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7-4-14

(x+7)2+(y+5)2 = 16 Centre of circle: (-7, -5) Radius: 4

If you mean 10+2y = 16 then the solution is y = 3

No.

8(3) - 16 = 324 - 16 = 38 = 3==========obviously not

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7-4-14

Without any plus or minus signs or an equality sign the given terms can't be considered to be an equation.

4x-2y=16 has the solution points (0,-8) and (4, 0) at the coordinate axes, and wherever y= 4(x-4).

16

y = (x + 2)2 andy = (2x)2(x-2)2 + (y-16)2 = 0

The center of the circle is at (-7, 5)

2y = 4x - 16 5y = 4x + 8 Subtract the first equation from the second: 3y = 24 so that y = 8 Substitute this into the first equation: 16 = 4x - 16 ie 32 = 4x so that x = 8 So the solution is (8, 8)

(x+7)2+(y+5)2 = 16 Centre of circle: (-7, -5) Radius: 4

The solutions are: x = -2 and y = 4

If you mean 10+2y = 16 then the solution is y = 3

a = 16

There is no solution to the equation 32'9 and 11 16 plus 32'9 and 11 16.