(5, -8)
Add 2.9 to both sides. y = 8.2
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
It's the equation of a straight line with a slope of -3, that crosses the y-axis at y= -1 . Every point on the line is a solution to the equation. There are an infinite number of them.
There are infinitely many ordered pairs - each pair representing a different point on the infinite line described by the equation.
In the Cartesian plane, each point has two coordinates. Point 6 and point 8 are not sufficiently uniquely defined.
3x-4y-6 = 0
You find the gradient of the curve using differentiation. The answer is 0.07111... (repeating).
No line described, but here is the point slope form. Y - Y1 = m(X - X1) =============
(4, -7)
A linear equation is the equation of a line and that consists of an infnite number of points. What you have, in x = -4 and y = -1/3, is a single point. A single point is not a line and so there cannot be a linear equation (suitable for a line) to represent a point.
Thanks to the limitations of the browser, it is not possible to read the equation of the line. Perhaps you could use words - such as "plus", "minus" and "equals" rather than the symbols and resubmit.