Wiki User
∙ 13y ago(5, -8)
Wiki User
∙ 13y ago79
If you mean: y -3 = 2(x -1) then y = 2x+1 and the point was (1, 3)
Without an equality sign the given expression can't be considered to be an equation.
Without an equality sign the given terms can't be considered to be an equation of a straight line.
16.1
(2, 11)
79
That of course would depend on the straight line equation that has not been given and so therefore an answer is not possible.
Finding the point that lies on the line described by the equation y - 8 - 3x - 6 can be easily found. Plug in the appropriate (x,y) values, one at a time, and you will find the value for the variable you did not plug in/
A point lies on a line if the coordinates of the point satisfy the equation of the line.
It is every point in the plane that lies on the straight line defined by the equation -5x + 4y = -3. Since there are an infinite number of points on that line, there is no point in trying to list them.
If you mean: y -3 = 2(x -1) then y = 2x+1 and the point was (1, 3)
Without an equality sign it can not be considered to be an equation
it lies in the 2nd and 4th quadrants
The given expression is not an equation because it has no equality sign
(6,2)
A number of point lies on it...................(-2,-44), (-1,-19),(0,6), (1,31), (2, 56)...............