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There cannot be such a polynomial.

If a polynomial has rational coefficients, then any complex roots must come in conjugate pairs. In this case the conjugate for 2-3i is not a root. Consequently, either

(a) the function is not a polynomial, or

(b) it does not have rational coefficients, or

(c) 2 - 3i is not a root (nor any other complex number), or

(d) there are other roots that have not been mentioned.

In the last case, the polynomial could have any number of additional (unlisted) roots and is therefore indeterminate.

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To find all rational roots of a polynomial equation, you can use the Rational Root Theorem. This theorem states that any rational root of a polynomial equation in the form of (anxn an-1xn-1 ... a1x a0 0) must be a factor of the constant term (a0) divided by a factor of the leading coefficient (an). By testing these possible rational roots using synthetic division or polynomial long division, you can determine which ones are actual roots of the equation.


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Where p is a factor of the leading coefficient of the polynomial and q is a factor of the constant term.?

Anywhere. Provided it is not zero, and number p can be the leading coefficient of a polynomial. And any number q can be the constant term.


What is the number in front of the term with the highest degree in a polynomial?

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