2-dimensional Cartesian space is naturally split into four quadrants, with one quadrant defined by x>0, y>0; one defined by x<0, y>0; one defined by x<0, y<0; and, one defined by x>0, y<0.
None. The coordinate lines between the quadrants don't belong to any of the quadrants.
The quadrants formed by the x and y axes are numbered anticlockwise from the quadrant in which both coordinates are positive (which is quadrant I). Thus negative x and positive y is in the quadrant II.
4
infinite number of axes
No, because point on the axes are not in any of the quadrants.No, because point on the axes are not in any of the quadrants.No, because point on the axes are not in any of the quadrants.No, because point on the axes are not in any of the quadrants.
False. The axes and the origin are not in any quadrant.
The coordinate plane is divided into four quarters by the axes. These are the four quadrants.
The axes.
The axes form the boundaries of the quadrants but not part of them. So points on the axes do not belong to any quadrant.
Quadrants result when a coordinate plane is divided by its axes in fours.
quadrants
I assume you mean (8, 0). If one or both of the coordinates are zero, the point is not in any of the four quadrants. Instead, it is on the axes - between two quadrants.
A sphere is not usually divided into 4 quadrants. Dividing by 2 along each of the 3 orthogonal axes partitions the sphere into 8.
In the context of a circle or the coordinate plane, quadrants are the four quarters defined either by two mutually perpendicular radii or the coordinate axes.
The coordinate or Cartesian plane is divided into four quadrants by the axes. The axes, themselves, do not belong to any quadrant. Assuming the normal x and y-axes, Quadrant I : x > 0, y > 0 Quadrant II : X < 0, y > 0 Quadrant III : X < 0, y < 0 Quadrant IV: X > 0, y < 0 That's it. No special sides, nothing to solve.
The x and y axes separate the coordinate plane into 4 quadrants.