1 + 1 = 0 in binary. Why does this happen?
Note: Adding binary numbers is related to modulo 2 arithmetic.
Let's review mod and modular arithmetic with addition.
modulus 2 is the mathematical term that is the remainder from the quotient of any term and 2. For instance, if we have 3 mod 2, then we have 3 / 2 = 1 + ½. The remainder is 1. So 3 ≡ 1 mod 2.
What if we want to add moduli?
The general form is a mod n + b mod n ≡ (a + b) mod n.
Now, for the given problem, 1 mod 2 + 1 mod 2 ≡ 2 mod 2. Then, 2 mod 2 ≡ 0 mod 2.
Therefore, 1 + 1 = 0 in binary.
x = 0
1111 + 0001 + 1000 + 0100 = 11100 Remember that in binary, 1 + 1 = 10 (0 carry 1) and 1 + 1 + 1 = 11 (1 carry 1).
1 In binary numbering means on 0 In binary numbering means off
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
x = -½
100101 1 times 2^0 = 1 PLUS 0 times 2^1 = 0 PLUS 1 times 2^2 = 4 PLUS 0 times 2^3 = 0 PLUS 0 times 2^4 = 0 PLUS 1 times 2^5 = 32 EQUALS 37
When you are working in binary arithmetic.
Yes because if 1+0=1 than 0 plus b equals b
1 plus 1 plus 1 plus 1 equals 1 times 4. 1 times 4 equals 4. 4 minus 4 equals 0. 0
( 1 0 1 ) + ( 1 0 1 ) = 1 0 1 0
It equals 7
In binary this would be written as 1010. This is because in binary (from right to left) the digits in this number mean:(0 * 20) + (1 * 21) + (0 * 22) + (1 * 23).This is equal to (0 * 1) + (1 * 2) + (0 * 4) + (1 * 8), which equals 0 + 2 + 0 + 8, which equals 11 (in decimal).
It equals 6
This will be in binary arithmetic, i.e. base 2 arithmetic.
2
If it's 1 +-1 =0
In binary this would be written as 1011. This is because in binary (from right to left) the digits in this number mean: (1 * 20) + (1 * 21) + (0 * 22) + (1 * 23). This, of course, is equal to (1 * 1) + (1 * 2) + (0 * 4) + (1 * 8), which equals 1 + 2 + 0 + 8, which equals 11 (in decimal).