it would be secant, 1/cosine
No.-1
[ cos(Θ) ]-1 = 1/cosine(Θ) = secant(Θ)
The cosine of anything is always a number between -1 and +1.3 - (-7) = 10
Sometimes. Not always.
The sine graph and the cosine graph are identical in shape, with the cosine graph shifted to the left by pi / 2, i.e. the sine starts at (x=0,y=0) and proceeds up with an initial slope of one, and the cosine starts at (x=0,y=1), and proceeds down with an initial slope of zero.
the graph of cos(x)=1 when x=0the graph of sin(x)=0 when x=0.But that only tells part of the story. The two graphs are out of sync by pi/2 radians (or 90°; also referred to as 1/4 wavelength or 1/4 cycle). One cycle is 2*pi radians (the distance for the graph to get back where it started and repeat itself.The cosine graph is 'ahead' (leads) of the sine graph by 1/4 cycle. Or you can say that the sine graph lags the cosine graph by 1/4 cycle.
Well, the easiest way to go at it is simply to remember thatthe sine and cosine of any angle are always less than 1 .
Cosine of 1 degree is about 0.999848. Cosine of 1 radian is about 0.540302.
The sine and the cosine are always less than one.
-1<cosine<1
Cosine (0) = 1 Sin(0) = 0 The sine and cosine curves are two intertwining curves, that complement each other, hence the words 'Sine (Curve) and Cosine ( COmplementary Curve).
The cosine function, like all of the trigonometric functions, is periodic about the rotation around a circle. Since the cosine is defined as the adjacent/hypotenuse of a right triangle, you can clearly see that its value can never be greater than one or less than -1 since the hypotenuse is always longer than the adjacent side. It turns out that, indeed, the cosine's range is from -1 to 1, written [-1,1].
it would be secant, 1/cosine
The cosine of 2pi is 1. In fact, for every integer N, the cosine of 2 N pi is 1.
No.-1
Secant is 1 over cosine and cosine 0 equals 1.