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That's not always the case. One formula for power dissipated is:
P = IR
So, a higher resistance means that more power is dissipated - if the current is the same. The reason for this is precisely that resistance is related to the conversion of electrical energy into heat.
However, if you put a higher resistance across a specific voltage, you'll get less power dissipation, not more, since less current will flow at a higher resistance.
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What is the formula for exponential decay?
y=a(1-r) to the t power
Find the area of the largest square incribed in a circle?
A circle of radius, r, has area pi r2. The largest square inside it is made up of four isosceles triangles whose equal sides are of length, r, and thus has area 1/2 r2. Thus the area of the contained square is 2 r2.
Calculate the resolving power if the wavelength is 600 nm and the numerical apertures are 0 0.2 0.4 0.6 0.8 and 1.0?
Use the Equation, Resolving Power=lambda/2(Numerical Aperture). So, given the values for Numerical Aperture(NA): If NA=0, then R=0, NA=0.2, then R=1500, NA=0.4, then R=750, etc. Simply solve the equation substituting the provided Numerical Aperture (NA) values in.
Why power waveform is not symmetrical to X-Axis in R-L circuit?
Because power dissipated in rl circuit is given by p= 1/2(Li²)+ i²R which will give a curve and not a linear graph. Secondly the graph is a cosine curve ,with a phase difference between current and voltage. Hence the waveform is not symmetrical to x-axis .
How do you find the radius when the circumfrence is given?
The circumference (not circumfrence!) is given by the equation C = 2*pi*r where r is the radius. So r = C/(2*pi) where pi is the irrational number that is approx 3.14159 or even more approximately, 3.14.
Reactance is not dissipate energy so why you are calculating in the account of resistance?
While reactive loads do not dissipate the reactive component of the power supply current, these currents are very real. They must be generated, and so must be taken into account when designing the generator. They also flow in the feeder conductors, cause I squared R power losses and heat, and must be taken into account when sizing the conductors.
23V 470 ohms what is P?
The power (P) can be calculated using the formula P = V^2 / R, where V is the voltage (23V) and R is the resistance (470 ohms). Plug these values into the formula to find the power in watts.
Why does India have the largest number of diabetes cases?
Because INDIANS r more interested in sweets & even they r sweet:))
Which sector of organization uses the largest volume of gas in Bangladesh?
Power Development Board (PDB) R. DEV (JnU)
How can you work out the power of a resistor?
It depends what you mean by your question. Ohms Law is the key. Power in a resistor is wasted as heat. If a resistor has 1 volt across it and passes a current of 1 amp, it will consume/dissipate one Watt of power ,and must therefore have a resistance of one ohm. To work out the power rating of a resistor required, use V x I = P V is voltage I is current in Amps P is power in Watts R is resistance in ohms V=I X R. I=V/R R=V/I Ohms Law is the fundamental equation of electricity and must be understood before you can go further.
Which wave is the largest in the electrocardiogram?
The largest wave is the R
What are the cities with the largest population?
Well the top two r New York and Cleveland but there r alot more u can find by Google or bing or ask.
How do you get more power cards?
I think you can get them at toys r us for $2-10
2 resistors unequal value are in parallel. Would the power dissipated by the resistor with larger ohmic value be greater than the power dissipated by the resistor of lesser value?
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
Which electric heater will yield the greater heat output a large resistance in the coil or a small resistance in the coil?
A small resistance in the coil will yield greater heat output in an electric heater. This is because a small resistance allows for a larger current to flow through the coil, which in turn generates more heat due to the increased power dissipation (P = I^2 * R).
Which artery starts with the letter r?
there are more than one. But off the top of my head... Renal Artery is probably the largest
Does resistance depends upon the dimension?
The basic relation to calculate resistance tells us: R = rho*l/A with R = resistance [Ohm] rho = resistivity [Ohm*meter] l = length [m] A = surface area [m^2] So, the resistance (given a certain resistive material) merely depends on the ratio between the length and the surface area of a resistor. Resisotrs tend to be bigger if they have to dissipate more power, for mor heat needs to be lost.
