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It isn't. The derivate of sin x = cos x.

It isn't. The derivate of sin x = cos x.

It isn't. The derivate of sin x = cos x.

It isn't. The derivate of sin x = cos x.

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15y ago

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Derivative of cosx?

The derivative of cos(x) is negative sin(x). Also, the derivative of sin(x) is cos(x).


What is the derivative of cos x sin x divided by cos x sin x?

(cos x sin x) / (cos x sin x) = 1. The derivative of a constant, such as 1, is zero.


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d/dx cosx=-sin x


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Every fourth derivative, you get back to "sin x" - in other words, the 84th derivative of "sin x" is also "sin x". From there, you need to take the derivative 3 more times, getting:85th derivative: cos x86th derivative: -sin x87th derivative: -cos x


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The derivative with respect to 'x' of sin(pi x) ispi cos(pi x)


When does cos x equal -sin x?

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sin integral is -cos This is so because the derivative of cos x = -sin x


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Because the slope of the curve of sin(x) is cos(x). Or, equivalently, the limit of sin(x) over x tends to cos(x) as x tends to zero.


Differentiate y equals xsinx plus cosx?

y = x sin(x) + cos(x)Derivative of the first term = x cos(x) + sin(x)Derivative of the second term = -sin(x)y' = Sum of the derivatives = x cos(x) + sin(x) - sin(x)= [ x cos(x) ]


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To differentiate y=sin(sin(x)) you need to use the chain rule. A common way to remember the chain rule is "derivative of the outside, keep the inside, derivative of the inside". First, you take the derivative of the outside. The derivative of sin is cos. Then, you keep the inside, so you keep sin(x). Then, you multiple by the derivative of the inside. Again, the derivative of sinx is cosx. In the end, you get y'=cos(sin(x))cos(x))


What is the second derivitive of sec x?

Write sec x as a function of sines and cosines (in this case, sec x = 1 / cos x). Then use the division formula to take the first derivative. Take the derivative of the first derivative to get the second derivative. Reminder: the derivative of sin x is cos x; the derivative of cos x is - sin x.