It isn't. The derivate of sin x = cos x.
It isn't. The derivate of sin x = cos x.
It isn't. The derivate of sin x = cos x.
It isn't. The derivate of sin x = cos x.
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Cos (x) = -Sin(x) 1 = -Sin(x) / Cos (x) 1 = -Tan(x) Tan(x) = -1 x = Tan^-1(-1( x = -45 degrees = - pi /4 , 3pi/4, 5pi/4 ....
To differentiate y=sin(sin(x)) you need to use the chain rule. A common way to remember the chain rule is "derivative of the outside, keep the inside, derivative of the inside". First, you take the derivative of the outside. The derivative of sin is cos. Then, you keep the inside, so you keep sin(x). Then, you multiple by the derivative of the inside. Again, the derivative of sinx is cosx. In the end, you get y'=cos(sin(x))cos(x))
0.5*cos(x)/sqrt(sin(x))
The derivative of sin(x) is cos(x).
d/dx (cos x)^2 using the rule of chain, take derivative of the external, times derivative of the internal = 2 (cos x)(-sin x) =-2sinx cos x = - sin(2x)