Every fourth derivative, you get back to "sin x" - in other words, the 84th derivative of "sin x" is also "sin x". From there, you need to take the derivative 3 more times, getting:85th derivative: cos x86th derivative: -sin x87th derivative: -cos x
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The 1st derivative of the sin is cos; the 2nd is -sin; 3rd is -cos; 4th is sin; then repeats every fourth time. So 84 th is the sin; 85th cos; 86th -sin; and 87th derivative is -cos
The derivative of sin(x) is cos(x). Coefficients act like constants and always remain in derivatives. So, the derivative is -2cos(x).
2xsin2x+2x2sinxcosx
Since 8 is a constant, you can use the rule for constants.In other words, the derivative is 8 times the derivative of cos x.
Derivative of sin x = cos x, so chain rule to derive 8x = 8 , answer is 8cos8x
The derivative of 3cos(x) is -3sin(x). This can be found using the chain rule, which states that the derivative of a composition of functions is the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function. In this case, the derivative of cos(x) is -sin(x), and when multiplied by the constant 3, we get -3sin(x) as the derivative of 3cos(x).