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Subjects>Math>Other Math

What is the derivative of sinπx?

Anonymous

∙ 15y ago

Updated: 4/28/2022

The derivative with respect to 'x' of sin(pi x) is

pi cos(pi x)

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∙ 15y ago

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More answers

Cos x is the derivative of Sin x.

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∙ 15y ago

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Continue Learning about Other Math

What is the derivative of sin x minus cos x?

d/dx(sinx-cosx)=cosx--sinx=cosx+sinx

What is the derivative of cos x?

d/dx(-cosx)=--sinx=sinx

What is the derivative of 7 to the power of cosx?

derivative (7cosx) = -ln(7) 7cosx sinx dx

How do you differentiate sine x squared?

Using the Chain Rule :derivative of (sinx)2 = 2(sinx)1 * (derivative of sinx)d/dx (Sinx)2 = 2(sinx)1 * [d/dx (Sinx)]d/dx (Sinx)2 = 2(sinx) * (cosx)d/dx (Sinx)2 = 2 (sinx) * (cosx)d/dx (Sinx)2 = 2 sin(x) * cos(x)

Find the derivative of sinxcosx?

(cosx)^2-(sinx)^2

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Related Questions

What is the derivative of -cosx?

-sinx

How do you take the derivative of a trig function?

Trig functions have their own special derivatives that you will have to memorize. For instance: the derivative of sinx is cosx. The derivative of cosx is -sinx The derivative of tanx is sec2x The derivative of cscx is -cscxcotx The derivative of secx is secxtanx The derivative of cotx is -csc2x

What is the derivative of sin x minus cos x?

d/dx(sinx-cosx)=cosx--sinx=cosx+sinx

What is the derivative of negative sinx?

-cos(x)

What is the anti-derivative of 4cosx divided by sinx to the power of 2?

2

What is the derivative of cos x?

d/dx(-cosx)=--sinx=sinx

What is the derivative of 7 to the power of cosx?

derivative (7cosx) = -ln(7) 7cosx sinx dx

Find derivative of sinx using first principle?

The derivative of sin(x) is cos(x).

How do you differentiate sine x squared?

Using the Chain Rule :derivative of (sinx)2 = 2(sinx)1 * (derivative of sinx)d/dx (Sinx)2 = 2(sinx)1 * [d/dx (Sinx)]d/dx (Sinx)2 = 2(sinx) * (cosx)d/dx (Sinx)2 = 2 (sinx) * (cosx)d/dx (Sinx)2 = 2 sin(x) * cos(x)

Find the derivative of sinxcosx?

(cosx)^2-(sinx)^2

What is the derivative of 1 divided by sinx?

y=1/sinxy'=(sinx*d/dx(1)-1*d/dx(sinx))/(sin2x)y'=(sinx*0-1(cosx))/(sin2x)y'=(-cosx)/(sin2x)y'=-(cosx/sinx)*(1/sinx)y'=-cotx*cscx

Find the critical numbers of sinx plus cosx?

f(x)=sinx+cosx take the derivative f'(x)=cosx-sinx critical number when x=pi/4

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