The slope formula is defined as the rise over the run, a.k.a the change in Y over the change in X.
m= (y1-y2)/(x1-x2).
For a Vertical Line, the rise is infinite while the run is zero, suggesting a slope of infinity/zero (because the slope is the rise over the run).
Zero can be put into infinity an infinite amount of times, describing an INFINITE SLOPE, which limit calculus is required to reveal. However, for algebra students, this value, infinity, or the infinite slope, is described as UNDEFINED. This is because algebra students have not yet received sufficient math tools to define infinity! Be patient and don't get too excited, calculus will reveal much :)
SO...
For CALCULUS students: Vertical lines have an infinite slope
For ALGEBRA students: Vertical lines have an undefined slope
You need a pair of coordinates to work out the slope-intercept equation.
Hello, the actually way to find it out is if you Half the sum of the parallel sides x The vertical distance between them. Eg. 1/2 (A+B) x Height.
To work out the equation of a straight line the slope and an (x, y) coordinate must be given
There is an infinite number of answers. Here is how to work it out The equation for any line is y = mx +c where m is the slope of the line and c, the point where the line crosses the y axis. Now put the point (-1, 5) into the equation: ==> 5 = -m +c ==> c = 5 +m Then just substitute different values for m (the slope) e.g. if the slope is 2, then c=7 so the line is y = 2x +7 e.g. if the slope is -6, then c = -1 so the line is y = -6x -1 These two lines intersect at (-1, 5) You can choose any slopes you like (including fractions) and you will get a pair of lines that intersect at (-1,5)
efficiency formula is (Wout/Win)*100% Wout is the work done by the machine is called the output work Win is the work done by you on a machine is called the input work efficiency= useful work output/work input For science, the effiency is: AMA/IMA * 100
The slope of a vertical line is undefined. It either slants straight up or straight down-- you can not say which. The formula for slope does not work in this case because the denominator is zero.
A vertical line does not have a defined slope. If you think of slope as a fraction, it would be dividing by zero, which doesn't work. So, basically, no solution
vertical lift versus slope the work done is the same (force * distance), but with a say 30 degree slope you need only half the force but need to travel twice as far to raise the load the same height vertically
Perpendicular, or "normal", means that two lines meet at right angles. The two lines cross in such a way that they form 4 equal angles between them.If you work with coordinates, the product of the slopes of two perpendicular lines are minus 1. For example, if a certain line has a slope of 2, another line, perpendicular to it, will have a slope of -1/2.
If two straight lines cut one another, the vertical, or opposite, angles shall be equal.
It is probably referring to #5 of the work. Perpendicular lines and negative and reciprocal slopes. EX: The slope is 2, the perpendicular form is -1/2
Perpendicular lines = Right Angles, thus any right angle related things work, and you know the angle of one of the 3 (90 degrees) so the perpendicular line as a slope of 90 minus the the angle of the undefined: Since the angles of a triangle must add to 180 Undefined + Perpendicular + Right Angle (90) = 180 Or something like that... been a while since I did geometry... hope this helps * * * * * A line with an undefined slope is a vertical line and so a line that is perpendicular to it is a horizontal line. In the coordinate plane, that would be a line with the equation y = c (for some constant c).
It would be worksheet, which would be contained in a workbook.
The man who is climbing on a slope is doing more work.
8
To work out the equation of a straight line a pair of coordinates are needed or a coordinate and its slope. But in general when lines are parallel to each other on the Cartesian plane they have the same slope but with different y intercepts.
Lifting a 50 kg sack a vertical distance of two meters requires more work because work is equal to force multiplied by distance. In this case, the force is greater (50 kg as opposed to 25 kg) even though the distance is shorter.