There is an infinite number of answers. Here is how to work it out
The equation for any line is y = mx +c where m is the slope of the line and c, the point where the line crosses the y axis.
Now put the point (-1, 5) into the equation:
==> 5 = -m +c
==> c = 5 +m
Then just substitute different values for m (the slope)
e.g. if the slope is 2, then c=7 so the line is y = 2x +7
e.g. if the slope is -6, then c = -1 so the line is y = -6x -1
These two lines intersect at (-1, 5)
You can choose any slopes you like (including fractions) and you will get a pair of lines that intersect at (-1,5)
2
Sometimes. Not always.
y = x - 1 y - x = 3 y = x - 1 y = x + 3 Since both equations represent straight lines that have equal slopes, 1, then the lines are parallel to each other. That is that the lines do not intersect, and the system of the equations does not have a solution.
Two linear equations (or lines) with the same y-intercept and different slopes are intersecting lines. They intersect at the y-intercept. If the slopes are negative reciprocals (ex: one slope is 3 and one slope it -1/3) then they are perpendicular lines.
None. If you rearrange each equation into slope intercept form ( y = mx + b), see below, you'll find that both equations have the same slope. Therefore they are parallel which also means would not intersect. Since the lines wouldn't intersect there is no solution to the system of equations.x + 3y = 23y = -x + 2y = (-1/3)x + 2/32x + 6y = -36y = -2x - 3y = (-1/3)x - (1/2)
They intersect at points (-2/3, 19/9) and (3/2, 5) Solved by combining the two equations together to equal nought and then using the quadratic equation formula to find the values of x and substituting these values into the equations to find the values of y.
2
Sometimes. Not always.
Where the lines intersect that gives the values for x and y in the two equations. The lines should intersect at (1, -3) because x = 1 and y = -3
Those two statements are linear equations, not lines. If the equations are graphed, each one produces a straight line. The lines intersect at the point (-1, -2).
A linear system is a set of equations where each equation is linear, meaning it involves variables raised to the power of 1. Solving a linear system involves finding values for the variables that satisfy all the equations simultaneously. This process is used to find solutions to equations with multiple variables by determining where the equations intersect or overlap.
If it is a linear system, then it could have either 1 solution, no solutions, or infinite solutions. To understand this, think of two lines (consider a plane which is just 2 dimensional - this represents 2 variables and 2 equations, but the idea can be extended to more dimensions).If the 2 lines intersect at a point, then that point represents a solution. If the lines are parallel, then they never intersect, and there is no solution. If the equations are such that they are just different ways of describing the same line, then they intersect at every point, so there are infinite solutions. If you have more than 2 lines then maybe some of them will intersect, but this is not a solution for the whole system. If all lines intersect at a single point, then that is the single solution for the whole system.If you have equations that describe something other than a straight line, then it's possible that they may intersect in more than one point.
first get both your equations into standard form... x + 2y = 9 (equation 1) x + 2y = 13 (equation 2) multiply equation 1 by (-1) -x - 2y = -9 x + 2y = 13 add the equations together 0 + 0 = 4 0 = 4 since the equations dont equal out then these equations do not intersect and are therefore parallel. PARALLEL is your answer
y = x - 1 y - x = 3 y = x - 1 y = x + 3 Since both equations represent straight lines that have equal slopes, 1, then the lines are parallel to each other. That is that the lines do not intersect, and the system of the equations does not have a solution.
Two linear equations (or lines) with the same y-intercept and different slopes are intersecting lines. They intersect at the y-intercept. If the slopes are negative reciprocals (ex: one slope is 3 and one slope it -1/3) then they are perpendicular lines.
1
-2