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What are two equations that intersect at -1 5 and how did you find this answer?
Wiki User
∙ 8y ago
There is an infinite number of answers. Here is how to work it out
The equation for any line is y = mx +c where m is the slope of the line and c, the point where the line crosses the y axis.
Now put the point (-1, 5) into the equation:
==> 5 = -m +c
==> c = 5 +m
Then just substitute different values for m (the slope)
e.g. if the slope is 2, then c=7 so the line is y = 2x +7
e.g. if the slope is -6, then c = -1 so the line is y = -6x -1
These two lines intersect at (-1, 5)
You can choose any slopes you like (including fractions) and you will get a pair of lines that intersect at (-1,5)
Wiki User
∙ 8y ago
Wiki User
∙ 8y agoy - 5 = x + 1 which is equivalent to x - y + 6 = 0and
y - 5 = 2*(x + 1) = which is equivalent to 2x - y + 7 = 0
In general, y - 5 = m*(x + 1), where m is a non-zero real number will be another such line.
Wiki User
∙ 8y agoThat would probably be simplest with straight lines. Use the point-slope equation of a line. Use any arbitrary slope.
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Does the graph of a system of equations intersect at more than 1 point?
Sometimes. Not always.
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How wold you classify two linear equations have the same y-intercept and different slopes?
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What are the solutions do these equations have x plus 3y equals 2 and 2x plus 6y equals -3?
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Does this system of equations have one solution no solutions or an infinite number of solutions 2x - y equals 8 and x plus y equals 1?
Solve both equations for y, that is, write them in the form y = ax + b. "a" is the slope in this case. Since the two lines have different slopes, when you graph them they will intersect in exactly one point - therefore, there is one solution.
Where do the curves of y equals 4x squared -2x -1 and y equals -2x squared plus 3x plus 5 intersect?
They intersect at points (-2/3, 19/9) and (3/2, 5) Solved by combining the two equations together to equal nought and then using the quadratic equation formula to find the values of x and substituting these values into the equations to find the values of y.
Does the graph of a system of equations intersect at more than 1 point?
Sometimes. Not always.
How do you solve the system by graphing -5x-y equals -2 x-3y equals 10?
Where the lines intersect that gives the values for x and y in the two equations. The lines should intersect at (1, -3) because x = 1 and y = -3
What type of lines are y equals 2x and y equals 4x plus 2?
Those two statements are linear equations, not lines. If the equations are graphed, each one produces a straight line. The lines intersect at the point (-1, -2).
Why do some systems of equations have one solution?
If it is a linear system, then it could have either 1 solution, no solutions, or infinite solutions. To understand this, think of two lines (consider a plane which is just 2 dimensional - this represents 2 variables and 2 equations, but the idea can be extended to more dimensions).If the 2 lines intersect at a point, then that point represents a solution. If the lines are parallel, then they never intersect, and there is no solution. If the equations are such that they are just different ways of describing the same line, then they intersect at every point, so there are infinite solutions. If you have more than 2 lines then maybe some of them will intersect, but this is not a solution for the whole system. If all lines intersect at a single point, then that is the single solution for the whole system.If you have equations that describe something other than a straight line, then it's possible that they may intersect in more than one point.
Where does x equals 9-2y and x plus 2y equals 13 intersect on a graph?
first get both your equations into standard form... x + 2y = 9 (equation 1) x + 2y = 13 (equation 2) multiply equation 1 by (-1) -x - 2y = -9 x + 2y = 13 add the equations together 0 + 0 = 4 0 = 4 since the equations dont equal out then these equations do not intersect and are therefore parallel. PARALLEL is your answer
Yx-1 y-x 3 find the solution for the system?
y = x - 1 y - x = 3 y = x - 1 y = x + 3 Since both equations represent straight lines that have equal slopes, 1, then the lines are parallel to each other. That is that the lines do not intersect, and the system of the equations does not have a solution.
How wold you classify two linear equations have the same y-intercept and different slopes?
Two linear equations (or lines) with the same y-intercept and different slopes are intersecting lines. They intersect at the y-intercept. If the slopes are negative reciprocals (ex: one slope is 3 and one slope it -1/3) then they are perpendicular lines.
What is the x and y of x-y equals -1 and -x plus y equals -1?
-2
What is the minimum number of times two planes can intersect?
1
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I have to prove if two lines intersect then they intersect in no more than one point I have to assume that lines intersect in MORE than one point i have to prove tht they intersect MORE than 1 wrong?
wrong!
