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Write an equation of the line containing the given point and parallel to the given line -8 2 in parenthesis 8x 9y 5 simplify type in the form of ymx b?
Wiki User
∙ 15y ago
Two lines are parallel if they have the same slope.
So from the given equation we are able to find the common slope such as:
8x + 9y + 5 = 0 subtract 8x and 5 to both sides
9y = -8x - 5 divide by 9 to both sides
y = (-8/9)x - 5/9
Using the slope m = -8/9 and the point (-8, 2) we write the point-slope form of the equation of the required line.
(y - y1) = m(x - x1)
(y - 2) = (-8/9)(x + 8)
y - 2 = (-8/9)x - 64/9
y - 2 + 2 = (-8/9)x - 64/9 + 2
y = (-8/9)x - 46/9 this is the slope-intercept form of the equation of the line that contain the point (-8, 2) and parallel to the given line.
Wiki User
∙ 15y ago
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