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How do you factor completely x to the fourth power minus 1?
So x4 - 1 is the difference of squares, so x4 - 1 = (x2 - 1)(x2 + 1) = (x + 1)(x - 1)(x2 + 1).
What is the x-intercept of Y equals x2-3x plus 2?
1 and 2
What is the effect on the graph of the equation y equals x2 plus 1 when it is changed to y equals x2 plus 5?
It keeps the same shape and size, but the whole thing rises four units on the paper, as if by magic.
Which of the binomials below is factor of this trinomial x2-5x plus 4 equals?
x2-5x+4 = (x-1)(x-4) when factord
How do you factor x raised to the 5th minus 1?
(x - 1)(x4 + x3 + x2 + x + 1)
1 plus x plus x2 plus x3 plus x4 plus plus x24 equals 49x25?
No.
Sum of series 1 plus x2 plus x4.....plus xn?
(xn+2-1)/(x2-1)ExplanationLet Y=1+x2+x4+...+xn. Now notice that:Y=1+x2+x4+...+xn=x2(1+x2+x4+...+xn-2)+1Y+xn+2=x2(1+x2+x4+...+xn-2+xn)+1Y+xn+2=x2*Y+1Y+xn+2-x2*Y=1Y-x2*Y=1-xn+2Y(1-x2)=1-xn+2Y=(1-xn+2)/(1-x2)=(xn+2-1)/(x2-1)
X plus 4 x plus 2 simplfied?
x4 +x2 =x2 (x2+1)
X4-2x3 plus 2x2 plus x plus 4 divided by x2 plus x plus 1 solutions?
(x4 - 2x3 + 2x2 + x + 4) / (x2 + x + 1)You can work this out using long division:x2 - 3x + 4___________________________x2 + x + 1 ) x4 - 2x3 + 2x2 + x + 4x4 + x3 + x2-3x3 + x2 + x-3x3 - 3x2 - 3x4x2 + 4x + 44x2 + 4x + 40R∴ x4 - 2x3 + 2x2 + x + 4 = (x2 + x + 1)(x2 - 3x + 4)
How do you solve x-1 plus x2-x plus x3-x2 plus x4-x3?
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
X4-x3 plus X2 -X plus 1?
It is a polynomial of the fourth degree in X.
X4 equals 2x3 plus 1?
Not necessarily.
Factor of 1-x4?
1 - x4 = (1 - x2)(1 + x2) = (1 - x)(1 + x)(1 + x2) (difference of squares)
How do you solve the limit as x approaches zero of 1 over x minus 4 plus 1 over x plus 4 all over x?
Limx→0 [ 1 / (x - 4) + 1 / (x + 4) ] / x = Limx→0 1 / (x2 - 4x) + 1 / (x2 + 4x) = Limx→0 (x2 + 4x) / (x4 - 16x2) + (x2 - 4x) / (x4 - 16x2) = Limx→0 (x2 + 4x - 4x + x2) / (x4 - 16x2) = Limx→0 2x2 / (x4 - 16x2) = Limx→0 2 / (x2 - 16) = 2 / (0 - 16) = -1/8
What is x4 divided by the square root of x4?
1
How do you factor x to the 8th power minus 1?
x8-1 becomes (x4 + 1) (x4 - 1) - perfect square and then (x4 + 1) (x2 - 1)(x2 + 1) - perfect square again. and then (x4 + 1)(x2 + 1)(x + 1)(x - 1) - perfect square again
X4-7x2 plus 1 equals 0 what is the value of x?
The equation is a quadratic in x2, so using the quadratic formula: x2 = [7 +/- √45]/2 so that x2 = 0.145898 or x2 = 6.854102 then x = √0.145898 = -0.381966 or +0.381966 or x = √6.854102 = -2.618034 or +2.618034
