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X4-2x3 plus 2x2 plus x plus 4 divided by x2 plus x plus 1 solutions?
Wiki User
∙ 14y ago
(x4 - 2x3 + 2x2 + x + 4) / (x2 + x + 1)
You can work this out using long division:
x2 - 3x + 4
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x2 + x + 1 ) x4 - 2x3 + 2x2 + x + 4
x4 + x3 + x2
-3x3 + x2 + x
-3x3 - 3x2 - 3x
4x2 + 4x + 4
4x2 + 4x + 4
0R
∴ x4 - 2x3 + 2x2 + x + 4 = (x2 + x + 1)(x2 - 3x + 4)
Wiki User
∙ 14y ago
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Is 2x2 plus 7 equals 79 linear or quadratic?
It is a quadratic equation that has 2 solutions
2x2 - 3x plus 7 equals 0?
2x2 - 3x + 7 = 0 doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (3 plus or minus the square root of -47) divided by 4.x = 0.75 + 1.713913650100261ix = 0.75 - 1.713913650100261iwhere i is the square root of negative 1
How do you factor 2x2-3x-6?
That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: (3 plus or minus the square root of 57) divided by 4.x = 2.6374586088176875x = -1.1374586088176875
What are the solutions of 2x2 plus 18x-20 equals 0?
Using the quadratic equation formula: x = 1 or x = -10
When dividing 2x2 - 4x plus 5 by x - 1 the remainder is 11?
2x2-4x+5 divided by x-1 Quotient: 2x-2 Remainder: 3
What is X3 plus X2 plus X plus 1 divided by X 1?
2x2+7/x1
Is 2x2 plus 7 equals 79 linear or quadratic?
It is a quadratic equation that has 2 solutions
2x2 - 3x plus 7 equals 0?
2x2 - 3x + 7 = 0 doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (3 plus or minus the square root of -47) divided by 4.x = 0.75 + 1.713913650100261ix = 0.75 - 1.713913650100261iwhere i is the square root of negative 1
How many real and imaginary solutions does the equation 2x2 -7x plus 9 equals x plus 1 have?
It has two equal solutions for x which are x = 2 and x = 2
What is the factorization of 2x2-6X plus 24?
There are no solutions to this quadratic equation because the discriminant is less than zero.
How do you factor 2x2-3x-6?
That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: (3 plus or minus the square root of 57) divided by 4.x = 2.6374586088176875x = -1.1374586088176875
How do you factor 2x2-5x-5?
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (5 plus or minus the square root of 65) divided by 4 x = 3.265564437 x = -0.765564437
When dividing 2x2 - 4x plus 5 by x - 1 the remainder is 11?
2x2-4x+5 divided by x-1 Quotient: 2x-2 Remainder: 3
What are the solutions of 2x2 plus 18x-20 equals 0?
Using the quadratic equation formula: x = 1 or x = -10
What are the solutions for 2x squared plus 5x plus 3 minus 4x squared plus 22 equals 0?
First you should combine equal terms. For example, 2x2 and -4x2 can be combined as -2x2. Then you can use the quadratic formula.Additonal Answer:-2x2+5x+3-4x2+22 = 0Collect like terms: -2x2+5x+25 = 0Divide al terms by -1: 2x2-5x-25 = 0Factorise: (2x+5)(x-5) = 0Solutions are: x = -5/2 or x = 5
How many different real solutions are there for 2x2-3x plus 5 equals 0?
There are no real solutions. The discriminant (b squared -4ac) is less than 0, so there are 2 imaginary solutions and 0 real ones.
Is it possible to find three solutions of the equation x3 plus 2x2 plus 3x plus 6 equals 0 Explain why or why not?
The variable term, X^3, is a third order polynomial term and will render three solutions, though one of those may be zero.
