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What answer is equal to the sum in the expression below (3x3 plus 4x2 - 2x plus 1) plus (x4 - x3 plus 5x2 plus 2x plus 3)?
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
X4-2x3 plus 2x2 plus x plus 4 divided by x2 plus x plus 1 solutions?
(x4 - 2x3 + 2x2 + x + 4) / (x2 + x + 1)You can work this out using long division:x2 - 3x + 4___________________________x2 + x + 1 ) x4 - 2x3 + 2x2 + x + 4x4 + x3 + x2-3x3 + x2 + x-3x3 - 3x2 - 3x4x2 + 4x + 44x2 + 4x + 40R∴ x4 - 2x3 + 2x2 + x + 4 = (x2 + x + 1)(x2 - 3x + 4)
1 plus x plus x2 plus x3 plus x4 plus plus x24 equals 49x25?
No.
What is the answer if you Find all the roots of the equation x4 - 2x3 plus 14x2 - 18x plus 45 0 given that 1 plus 2i is one of its roots.?
The four roots are:1 + 2i, 1 - 2i, 3i and -3i.
X4 plus x2 equals 1?
4X + 2x = 1. Where x = 0.166666666666666666666666666666666666666 recurring.
4x8 plus 5x4 - 2x3 plus x2 - 1?
103
What are the solutions to the equation 2x 3 plus 4 equals 17?
2x3 + 4 = 17 2x3 = 13 x3 = 13 / 2 x = (13 / 2)1/3 x = 521/3 / 2
How do you calculate this sum 18-2x3 plus 1?
13
What is 5(2x3 plus 1)-4(6)?
60
What is the factor 2x3-8x2 plus 6x?
What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).
How do you find the imaginary roots of p of x equals x to the fourth plus 2x cubed plus x squared plus 8x minus 12?
p(x) = 0 => x4 + 2x3 + x2 + 8x - 12 = 0=> (x + 3)*(x - 1)*(x2 + 4) = 0So the imaginary roots of p(x) are the imaginary roots of x2 + 4 = 0that is x = ±2i
What is the f dashed x or deriative of 1 over 2xcubed plus 5?
f'(x) = 1/(2x3 + 5) rewrite f'(x) = (2X3 + 5) -1 use the chain rule d/dx (2x3 + 5) - 1 -1 * (2x3 + 5)-2 * 6x2 - 6x2(2x3 + 5) -2 ==================I would leave like this rather than rewriting this
