Well, well, well, look who's trying to divide X to the 4th power by X. Let me break it down for you - when you divide X to the 4th power by X, you simply subtract the exponents. So, X to the 4th power divided by X is just X to the power of 3. Easy peasy lemon squeezy!
Well, darling, when you divide x to the power of 8 by x squared, you subtract the exponents. So, x to the power of 8 divided by x squared is x to the power of 8 minus 2, which simplifies to x to the power of 6. So, there you have it, x to the power of 6 is the sassy answer you're looking for.
x squared
x^(ln(2)/ln(x)-1)
x-2(x)+4/x^2 -4=x-2x+4/x^2 -4=-x-4+4/x^2
If that is x to the power 0, then it = 1, irrespective of the value of x. Consider for example x =4. x squared is 16. To get from x to the power 2 to x to the power 1, you divide by x, giving 4 to the power 1 = 4. Similarly, to get from x to the power 1 to x to the power 0, you divide by x, giving 4 to the power zero = 1.
0.5556
2
X^4 divided by Y^2
x^(2-x-6)/x^(2-4) x^(-4-x)/x^-2(x^-2)*(x^(-2-6))= x^(-2-x)
0.04
X to the 9th power
(x4 * x10)/(x7)x14/x714 - 7 = 7= x7===
1
It is negative one divided by 4 multiplied by x to the power of 1.5 -1/(4(x^1.5))
Anything to the power 0 is 1. Using the laws of powers to get to x to the power n-1 from x to the power n you divide by n; eg to get 4 squared (16) from 4 cubed (64) you divide 64 by 4. If you start with x to the power 1 and want x to the power zero, you divide by x. And x divided by x is 1.
7
if y=7/(x^3)-4/xthenby the quotient ruley'=(((0)(x^3)-(7(3x^2))/((x^3)^2))-(((0x)-(4))/(x^2))