-2x+3y=1 3y=1+2x y=(1+2x)/3 Then proceed to find points by plugging in given or arbitrary values of x.
2x + 6y = 6Subtract 2x from each side:6y = -2x + 6Divide each side by 6:y = -1/3 x + 1The graph is a straight line, with a slope of [ -1/3 ], and intersecting the y-axis at the point [ y = 1 ].
(2x + 3)(x + 1 ) = 2x^2 +5x +3
a straight line with a slope of -2 and a y-intercept of 3
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.
-2x+3y=1 3y=1+2x y=(1+2x)/3 Then proceed to find points by plugging in given or arbitrary values of x.
2x + 6y = 6Subtract 2x from each side:6y = -2x + 6Divide each side by 6:y = -1/3 x + 1The graph is a straight line, with a slope of [ -1/3 ], and intersecting the y-axis at the point [ y = 1 ].
(2x + 3)(x + 1 ) = 2x^2 +5x +3
A graph that has 1 parabolla that has a minimum and 1 positive line.
2x plus y = -3 (subtract 2x from both sides) y = -2x - 3 slope = -2 y-intercept = -3
a straight line with a slope of -2 and a y-intercept of 3
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
6x2 + 11x + 3 = 6x2 + 9x + 2x + 3 = 3x(2x + 3) + 1(2x + 3) = (2x + 3)(3x + 1)
2,4
2x+1 because -2 +3 = 1
There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.