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How do I write the equation of a line that passes through the point 4 and -2 and has a slope of 2?
To do this, use the formula y = mx + b where b is the y-intercept and m is the slope.Since the slope is 2: y = 2x + bTo find b, substitute 4 for x and -2 for y: -2 = 2(4) + b, b = -2 - 2(4) = -10The equation of the line is y = 2x - 10
What is the slope of y equals 3x-2?
5
What is the x-intercept of 2x-y-2?
So, is that to say that 2x-y-2 = 0? Taking into consideration that y = mx + b ... 2x-2 = y y = 2x -2 In y = mx + b, the "b" is the y intercept the "m" is the slope To find the x intercept, make y = 0 and solve. 0 = 2x -2 2 = 2x x = 1
How do you find a y intercept of line with a slope of negative 2?
An equation of a line can be put into the form: y = mx + b, where m is the slope and b is the y-intercept. So if the slope is -2 the equation should be able to be rearranged into y = -2 + b, and the point (0,b) will be where the line intersects the y-axis.
What is the slope and y intercept to y equals x plus 2?
y = x + 2 Slope-intercept form is y = mx + b The slope, m, would be 1 and the y-intercept, b, would be 2
