-4
If: y = x+6 and y = 2x Then: x+6 = 2x And: 6 = 2x-x => 6 = x So: x = 6 and y = 12
2x=3-y 2y=12-x y=3-2x 2(3-2x)=12-x 6-4x=12-x -3x=6 x=-2 2(-2)=3-y -4=3-y y=7 x=-2 y=7
So, is that to say that 2x-y-2 = 0? Taking into consideration that y = mx + b ... 2x-2 = y y = 2x -2 In y = mx + b, the "b" is the y intercept the "m" is the slope To find the x intercept, make y = 0 and solve. 0 = 2x -2 2 = 2x x = 1
If you mean: y = x^2 -2x -8 then x = -2 or x = 4
4
The result of the equation x + 2y - 2x - y equals x simplifies to y - x.
-4
2x + 4 = y ...............2x + 4 = y ....................2x + 4 = y .............2*(-6)+ 4 = y x - y = 2 .......<=> ...x - 2x - 4 = 2 .....<=> ...x = -6......... <=>.... x = -6 ..............<=> y = - 8 x = - 6
If: y = x+6 and y = 2x Then: x+6 = 2x And: 6 = 2x-x => 6 = x So: x = 6 and y = 12
y=2x-3 y=-x-3
X + ( 2Y - 2X - Y ) is equal to Y - X
-3
y=f(x)= x(2x+y)=7 f(x)=2x^2 +xy -7 = 0 y=2x^2 +xy -7 y-xy -7 + 2x^2 = 0 y(1-x)=2x^2-7 y=(2x^2-7) / (1-x) Excuse the working. Y equals 2 X squared minus 7 all divided by 1-X
I presume you mean given y find x: Make x the subject: y = 2x + 3 => 2x + 3 = y => 2x = y - 3 => x = (y - 3)/2 which can also be expressed as: x = 0.5 y - 1.5
y=2x-4 y=2x-5 y=1 1=2x-4 -2x = -5 x=2/5 the solution is (x,y) = (2/5,1)
2x = y + 7 x - 2 = y substitute the y from the second equation into the first: 2x = x - 2 + 7 2x = x+5 x = 5 --> y = 5 - 2 y = 3