Q: What are the dimensions of a rectangle if the length is 5 feet longer than four times th width?

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length times width

8X36

If those are the dimensions of a rectangle, simply multiply length times width.

That would be 3 x 9 inches.

Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.

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length times width

They are 6 and 12

Without the dimensions, we won't be able to tell. The area of a rectangle is the length times the width. If those dimensions are in inches, the area will be in square inches.

18.4cm by 22.4cm

The dimensions work out as: length = 30 times the square root of 5 breadth = 40 times the square root of 5 check: (30 times sq rt of 5)*(40 times sq rt of 5) = 6000 square units

Area of a rectangle: length times width Width=11 Length= 11x3= 33 11x33= 363 square feet

Area of a rectangle is length times width, therefore if the length is two feet longer than the width then the length is 9 and the width is 7, when they are multiplied you get 63

8X36

If those are the dimensions of a rectangle, simply multiply length times width.

That would be 3 x 9 inches.

It is the area of the rectangle which is length times width

Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.