if unseeded, BOD = (D1-D2)/P
if seeded, BOD = ((D1-D2)-(B1-B2)f)/P
D1 = DO of diluted seeded wastewater
D2 = DO of wastewater after incubation
B1 = DO of diluted seed sample
B2 = DO of seed sample after incubation
f = ratio of seed volume in seeded wastewater test to seed volume in BOD test on seed
P = decimal fraction of wastewater sample used. (vol. of wastewater)/(vol. of dilution water plus wastewater)
Maybe that helps
The factors that can affect the biochemical oxygen demand (BOD) value in an experiment include the organic matter concentration in the sample, the microbial population present to break down the organic matter, the incubation time of the sample, and the temperature at which the incubation occurs. These factors can influence the rate at which oxygen is consumed in the sample, affecting the final BOD value measured.
Seeded BOD involves adding a known quantity of acclimated microorganisms to the BOD sample to speed up the decomposition process. Unseeded BOD relies on the naturally occurring microorganisms in the sample to break down the organic matter, which can take longer compared to seeded BOD. Seeded BOD may provide a more accurate and consistent measure of the organic load in a sample, while unseeded BOD can be influenced by the initial microbial population present in the sample.
Residual dissolved oxygen (DO) is the amount of oxygen remaining in a water sample after a specific time period during biochemical oxygen demand (BOD) testing. It is used to calculate the oxygen depleted by organic matter present in the sample, which helps in assessing the water quality and pollution levels.
It will be invaluable if (when) you need to calculate sample correlation coefficient, but otherwise, it has pretty much no value.
There are generally no standards for an absolute BOD5 value of drinking water. However, a sample with a BOD5 between 1 and 2 mg/L indicates a very clean water
The Biochemical Oxygen Demand (BOD) of a sample is the amount of dissolved oxygen required by aerobic microorganisms to breakdown organic matter in the sample.The test is simple:Measure the Dissolved Oxygen content of the sample (a)Place in a sealed darkened bottleIncubate for 5 days at 20'CMeasure the Dissolved Oxygen content of the incubated sample (b)Generally you're using this test to analyse contaminated water, so you'll want to dilute it first - it may be that aren't enough aerobic microorganisms present to give you a measurable result, in which case you'll need to inoculate the sample with a suitable culture.The BOD of the sample = a - bBOD is expressed in mg O2/L of sample.Extra CreditGenerally you're using this test to analyse contaminated water, so you'll want to dilute it first - it may be that aren't enough aerobic microorganisms present to give you a measurable result, in which case you'll need to inoculate the sample with a suitable culture.The BOD of a diluted innoculated sample = ((a - b) - BOD of inoculated culture) * dilution factor
The quantity of manganous sulphate added to a water sample for BOD testing is typically around 8 mg per liter of sample. This is used in conjunction with alkaline iodide azide solution to oxidize the organic matter present in the water sample, forming a brown precipitate. The amount of oxygen consumed during this process is then used to calculate the Biological Oxygen Demand (BOD) of the water sample.
80 mg/l
COD measures the amount of oxygen required to chemically oxidize (break down) organic and inorganic matter in a water sample, while BOD measures the amount of oxygen consumed by microorganisms during a biological process that breaks down organic matter. COD typically gives a higher value than BOD because it includes both the chemical and biological oxygen demand in the water sample.
0.1
BOD is the oxygen necessary for living organisms in a sample of water for the degradation of organic compounds.
Solve for y; calculate a few sample points (plug in a value for x, then calculate the corresponding value for y); plot on the graph. Two points should be enough in theory (this equation is a straight line), but a third point helps you confirm that your calculations are correct.Solve for y; calculate a few sample points (plug in a value for x, then calculate the corresponding value for y); plot on the graph. Two points should be enough in theory (this equation is a straight line), but a third point helps you confirm that your calculations are correct.Solve for y; calculate a few sample points (plug in a value for x, then calculate the corresponding value for y); plot on the graph. Two points should be enough in theory (this equation is a straight line), but a third point helps you confirm that your calculations are correct.Solve for y; calculate a few sample points (plug in a value for x, then calculate the corresponding value for y); plot on the graph. Two points should be enough in theory (this equation is a straight line), but a third point helps you confirm that your calculations are correct.