With constant velocity (v) the equation for distance can be d = vt, where d is the distance traveled (in miles), and t is the time (in hours). So at t= 2 hr, d = 90 mi, solve for v = (90 mi)/(2 hr) = 45 mi/hr (or mph). Check this at 5 hours: d = (45 mi/hr)*(5 hr) = 225 mi, which checks with the original problem.
315
If an object is traveling at a constant velocity, its acceleration is 0. Even if it traveled for 2 years.
110=2hrs 110 x 2=4hrs 4hrs=220 110/2 =55 55=1hr 220+55=275 275=5hrs {cloud9}
The distance traveled by an automobile moving at a constant velocity is equal to the product of the velocity and the time traveled. This relationship assumes no changes in velocity or direction during the motion.
The distance traveled by a truck driving at a constant speed compared with time.
The equation for constant speed is distance = speed x time, where distance is the total distance traveled, speed is the constant speed at which the object is moving, and time is the duration of travel.
D = 60T where T is expressed in hours.
It is the speed, which must be maintained at a constant value.
The car is moving at 45 mph (90 for 2, 225 for 5) After 9 hrs, car will have travelled 45 x 9. (you did not expect me to do all your homework?)
The equation relating acceleration, distance traveled, and time of fall is given by: distance = (1/2) * acceleration * time^2. This equation is derived from the kinematic equation for motion under constant acceleration.
No. The total distance traveled divided by constant speed is the time interval.
You multiply the speed at which you are traveling by the time spent traveling.