Q: A car is traveling at a constant velocity After 2 hrs the car has traveled 90 miles After 5 hrs the car has traveled 225 miles Assuming a linear equation fits how far will the car travel in 9 hrs?

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If an object is traveling at a constant velocity, its acceleration is 0. Even if it traveled for 2 years.

110=2hrs 110 x 2=4hrs 4hrs=220 110/2 =55 55=1hr 220+55=275 275=5hrs {cloud9}

D = 60T where T is expressed in hours.

Assuming that the car moves at a constant speed, you can use the standard formula for speed: distance = speed x time

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315

If an object is traveling at a constant velocity, its acceleration is 0. Even if it traveled for 2 years.

110=2hrs 110 x 2=4hrs 4hrs=220 110/2 =55 55=1hr 220+55=275 275=5hrs {cloud9}

The distance traveled by an automobile moving at a constant velocity is equal to the product of the velocity and the time traveled. This relationship assumes no changes in velocity or direction during the motion.

The equation for constant speed is distance = speed x time, where distance is the total distance traveled, speed is the constant speed at which the object is moving, and time is the duration of travel.

Assuming the rate of 60 mph is constant, traveling 60 mph means you are traveling one mile per minute. Since 45 seconds is 3/4 of a minute, you have traveled 3/4 of a mile, or3,960 feet

D = 60T where T is expressed in hours.

It is the speed, which must be maintained at a constant value.

With constant velocity (v) the equation for distance can be d = vt, where d is the distance traveled (in miles), and t is the time (in hours). So at t= 2 hr, d = 90 mi, solve for v = (90 mi)/(2 hr) = 45 mi/hr (or mph). Check this at 5 hours: d = (45 mi/hr)*(5 hr) = 225 mi, which checks with the original problem.

Not necessarily. The distance a car travels is determined by its speed and the time it spends traveling. If a car is traveling at a slower speed but for a longer period of time, it may not cover as much distance as a car traveling at a faster speed but for a shorter period of time. So, the longest time does not always correspond to the greatest distance traveled.

The equation relating acceleration, distance traveled, and time of fall is given by: distance = (1/2) * acceleration * time^2. This equation is derived from the kinematic equation for motion under constant acceleration.

No. The total distance traveled divided by constant speed is the time interval.